problem43_72

problem43_72 - 536 1 10 535 1 7 yr sec 10(3.156 yr 07 30...

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43.72: In terms of the number N of cesium atoms that decay in one week and the mass kg, 0 . 1 = m the equivalent dose is . 10 535 . 1 J) 10 (2.283 Sv) (3.5 kg) 0 . 1 ( so J), 10 283 . 2 ( MeV)) (0.51 (1.5) MeV) 66 . 0 ( ) 1 (( ) E (RBE) E RBE) (( Sv 5 . 3 13 13 13 e e × = × = × = + = + = - - N m N m N m N γ γ The number 0 N of atoms present is related to so , by λ 0 t Ne N N = . 10
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Unformatted text preview: 536 . 1 ) 10 535 . 1 ( sec 10 30 . 7 ) yr sec 10 (3.156 yr) 07 . 30 ( 693 . λ 13 days) sec 10 (8.64 days) 7 ( ) sec 10 30 . 7 ( 13 λ 1 10 7 4 1 10 × = × = = ⇒ × = × = × ×----e Ne N t...
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