problem43_76

# problem43_76 - b By trial and error the data is fit by a...

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43.76: a) A least-squares fit of the log of the activity vs. time for the times later than 4.0 hr gives a fit with correlation ( 29 6 10 2 1 - × - - and decay constant of 1 hr 361 . 0 - , corresponding to a half-life of 1.92 hr. Extrapolating this back to time 0 gives a contribution to the rate of about 2500/s for this longer-lived species. A least-squares fit of the log of the activity vs . time for times earlier than 2.0 hr gives a fit with correlation = 0.994, indicating the presence of only two species.
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Unformatted text preview: b) By trial and error, the data is fit by a decay rate modeled by ( 29 ( 29 ( 29 ( 29 hr 361 . hr 733 . 1 Bq 2500 Bq 5000 t t e e R--+ = . This would correspond to half-lives of 0.400 hr and 1.92 hr. c) In this model, there are 7 10 04 . 1 × of the shorter-lived species and 7 10 49 . 2 × of the longer-lived species. d) After 5.0 hr, there would be 3 10 80 . 1 × of the shorter-lived species and 6 10 10 . 4 × of the longer-lived species....
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