Selectivity Example - =2.49-kmol/s 1448 25.2-m3 s n = s...

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Unformatted text preview: fl£=2.49-kmol/s 1448 25.2-m3 s n =———— s 224-»:3 Component balances Ethylene: n1: 0.825(2.98-kmol/s)—§, —g2 Oxygen: 712 = 0.175(2.98-kmol/s)—%§1 —352 = 0 Ethylene Oxide: n3 = 6, Carbon Dioxide: 714 = 252 Water: n5 = 262 \ 1 Sum n = 2.98 — 34‘] = 2.49 We find 5, = 0.98 From the oxygen balance 0.175(2.98)—%(0.98)—352 = 0 0.175(2.98)—l(0.98) 62 = ———?i— = 0.0105 The yield of ethylene oxide is 0.98 —— 100: 4° 2(0.175)(2.98)X 9 A The selectivity is 0.98 2(00105) ...
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