# MAT-232 WA#2 - Name: Eleonor Lopez College ID: 0515654...

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Name: Eleonor LopezCollege ID: 0515654Thomas Edison State CollegeCalculus II (MAT-232)Section no.:6.2, 6.3, 6.4, 6.6, 3.2Semester and year: Jun 16Written Assignment 2Answer all assigned exercises, and show all work. Each exercise is worth 4 points.Section 6.24.Evaluate the integral.2222222222lnln,1,2ln11lnln2222111ln(ln)2222ln24xxdxudvuvvduux dvxxdudx vxxxxxxxdxdxxxdxxxxxxxdxxxcxxxc6.Evaluate the integral.WA 2, p. 122lnln1ln22xdxxuxdudxxdu dxxuxduuduxxucc  
18.Evaluate the integral.222sin1,2211sinsin221cos()cos22xx dxuxduxdxdudxxxuduuduxxuc 22.Evaluate the integral.12302332323233333233323332333231,32,12233331,3,2113333223992213993xxxxxxxxxxxxxxxxxxxxx e dxuxveduxdx dvedxx ex eIx edxexdxxedxux vedudx dvedxx eIxeedxx eIxeedxx eIxeecx e12333100223.64553927xxxx exeedxWA 2, p. 2
24.Evaluate the integral.21lnxx dx, from 6.2 #422lnln24xxxxxdxc222211lnln0.63624xxxxxdx46.Evaluate the integral using integration by parts and substitution.222222ln(4)1(4),2211ln( )ln( )22ln( ),1,111ln( )ln( )22ln2(4)ln(4)4ln(4)2xxdxuxduxdxdudxxxuduu duxwudvdudwdu vuuwdvwvvdwuuuduuuduuuuuxxxxxdxcSection 6.38.Evaluate the integral.WA 2, p. 3
4124443233sin (3)3,11sinsincossinsin (3)sin ( )13131sin ( )sincossinsincos(1cos2 )44442131sincos(1cos2 ),2 ,2,48214nnnxdxuxdudxnu duuuudunnxdxu duu duuuu duuuu duuuu du vu dvdudvdu     333113sincos(1cos )sincos(1cos )82416uuvdvuuv dv 333313sincos1cos4161313sincossinsincos2sin 241641613sin (3)cos(3)23sin 2(3)416uudvvdvuuvvcuuuucxxxxc    10.Evaluate the integral.

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