3200_solutions_hw13,14 - r1=1.61/2= 0.805 ksteel = 9.4...

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Unformatted text preview: r1=1.61/2= 0.805 ksteel = 9.4 Btu/h F r2=1.9/2 = 0.95 kglass = 0.022 Btu/h F r3=r2+1 = 1.95 kmagnesia = 0.038 @ 40F and =0.041@ 100F, use 0.039 r4=r3+1 = 2.95-------------------------------------------------- 16.12 Here is the solution manual solution. It is ok until the integration step in part (a), after which there is a mistake in rewriting the integrand (the square is moved to the wrong position). Go to the next page for the corrections. Note that the A o = A 1 = r 1 2 problem is here (1 + x 2 ) should be (1 + x) 2 Correction: - = + 2 1 1 2 ) 1 ( 1 T T L dT kA dx x q ) ( | ) 1 ( 1 2 1 T T kA x q L-- = +- ) ( 1 ) 1 ( 1 1 2 1 T T kA L q- = - + ) ( ) 1 ( ) 1 ( ) 1 ( 1 1 2 1 T T kA L L L q- = + +- + ) ( ) 1 ( 1 2 1 T T kA L L q- = +- ) ( ) 1 ( 2 1 1 T T L L kA q- + = X 16.12 (b) dz dT x A aT k q 2 1 )...
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This note was uploaded on 05/10/2008 for the course CHBE 3200 taught by Professor Meredith during the Spring '08 term at Georgia Institute of Technology.

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3200_solutions_hw13,14 - r1=1.61/2= 0.805 ksteel = 9.4...

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