HW5solncorrectedprob5 - machine A PA = -18000 machine B...

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17.15 given two machines service life A 1 service life B 2 ieff i A ($) B ($) first cost 10000 18000 Have to compare pumps after 2 years because that is the lowest multiple of their lifetimes compare machines after 2 years by calculating present worths
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Unformatted text preview: machine A PA = -18000 machine B PB=-18000 PB = -18000 i 0.25 Use solver to change the value of X to make the value of cell B16 equal to cell B20 i = 25% PA=-10000-10000/(1+ X ) define salvage value variable i...
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