Four bar link mechanism

Four bar link mechanism -...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
%------------------------------------------------------------- % 4-bar linkage position, velocity and acceleration analysis  % Abdullah Bin Jadid % Assignment 6 %------------------------------------------------------------- clc; clear;     % Clear cursor and clear previously defined variables  % Inputs DR = pi/180;R = input( 'Enter [r1, r2, r3, r4, rca, th1, th2, del3] (m  and deg)' ; r1 = 5; r2 = 2; r3 = 3; r4 = 3.5; rca = 3; th1)= 0*DR;  th2 = 70*DR;  del3 = 15*DR;    % Change degrees to radians r1x = r1*cos(th1);  r1y = r1*sin(th1);   % Position analysis: theta4 E = 2*r4*(r1*cos(th1) - r2*cos(th2)); F = 2*r4*(r1*sin(th1) - r2*sin(th2)); G = r1^2 + r2^2 - r3^2 + r4^2 - 2*r1*r2*cos(th1-th2); t(1) = (-F + sqrt(E^2 + F^2 - G^2)) / (G-E); % Crossed Branch t(2) = (-F - sqrt(E^2 + F^2 - G^2)) / (G-E); % Open Branch th4(1) = 2*atan(t(1));th4(2) = 2*atan(t(2));   % th3, coupler point, transmission angle; calculate for both branches for     i = 1:2,     ax = r2*cos(th2);  % theta3      ay = r2*sin(th2);
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern