problem27_42

problem27_42 - 27.42: a) = IBA = (6.2 A)(0.19 T)(0.050...

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Unformatted text preview: 27.42: a) = IBA = (6.2 A)(0.19 T)(0.050 m)(0.080 m) = 4.71 10 -3 N m. b) = IA = (6.2 A)(0.050 m)(0.080 m) = 0.025 A m 2 . c)Maximum torque will occur when the area is largest, which means a circle: 2R = 2(0.050 m + 0.080 m) R = 0.041 m. max = IBA = (6.2 A)(0.19 T) (0.04041 m) 2 = 6.22 10 -3 N m. ...
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This note was uploaded on 05/07/2008 for the course PHYS 4 taught by Professor Stuart during the Spring '08 term at UCSB.

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