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problem27_18 - 27.18 a F qvB sin B F 0.00320 109 N qv sin...

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27.18: a) θ sin qvB F = ° × × = = - - 90 sin ) s m 000 C)(500, 10 8(1.60 N 10 00320 . 0 sin 19 9 θ qv F B T. 00 . 5 = B If the angle θ is less than , 90 o a larger field is needed to produce the same force. The direction of the field must be toward the south so that B v × can be downward. b) θ qvB F sin = ° × × = = - - 90 sin T) C)(2.10 10 (1.60 N 10 60 . 4 sin 19 12 θ qB F
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