problem27_18

problem27_18 - 27.18: a) F = qvB sin F 0.00320 10 -9 N B= =...

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Unformatted text preview: 27.18: a) F = qvB sin F 0.00320 10 -9 N B= = qv sin 8(1.60 10 -19 C)(500, 000 m s ) sin 90 B = 5.00 T. If the angle is less than 90 o , a larger field is needed to produce the same force. The direction of the field must be toward the south so that v B can be downward. b) F = qvB sin F 4.60 10 -12 N v= = qB sin (1.60 10 -19 C)(2.10 T) sin 90 v = 1.37 10 7 m s . If is less than 90 o , the speed would have to be larger to have the same force. The force is upward, so v B must be downward since the electron is negative, so the velocity must be toward the south. ...
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This note was uploaded on 05/07/2008 for the course PHYS 4 taught by Professor Stuart during the Spring '08 term at UCSB.

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