ch4_ex

# ch4_ex - solution B). You take 15.0 mL of solution B and...

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Example #1 1.00 mL of a 3.50 x 10 –4 M solution of oleic acid is diluted with 9.00 mL of petroleum ether, forming solution A. 2.00 mL of solution A is diluted with 8.00 mL of petroleum ether, forming solution B. How many grams of oleic acid are 5.00 mL of solution B? (molar mass for oleic acid = 282 g/mol)? ( 29 ( 29 ( 29 ( 29 g 10 x 9.87 OA mol 1 OA g 282 L 10 x 5.00 mL 10.00 mL 2.00 mL 10.00 mL 1.00 M 10 x 3.50 6 - 3 4 - = -

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Example #2 You dissolve 15.71 g of NH4NO3 in 150.0 mL solution (call this solution A). You take 20.0 mL of solution A and add water until the total volume is 75.0 mL (call this
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Unformatted text preview: solution B). You take 15.0 mL of solution B and add 25.0 mL of water to it (call this solution C). You mix 10.0 mL of solution B and 10.0 mL of solution C (call this solution D). What is the concentration of ammonium nitrate in solution D? mol 0.1963 NO NH g 80.04 NO NH mol 1 NO NH g 15.71 3 4 3 4 3 4 = × Example #2 [ ] [ ] ( 29 ( 29 [ ] ( 29 ( 29 [ ] ( 29 ( 29 ( 29 ( 29 M 0.240 L 20.0 mL 10.0 M 0.131 mL 10.0 M 0.349 D M 0.131 mL 40.0 mL 15.0 M 0.349 C M 0.349 mL 75.0 mL 20.0 M 0.1309 B M 1.309 L 0.1500 mol 0.1963 A = + = = = = = = =...
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## This note was uploaded on 05/11/2008 for the course CHEM 025 taught by Professor Axe during the Spring '08 term at Pacific.

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ch4_ex - solution B). You take 15.0 mL of solution B and...

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