ch7_ex - Example #1 (Ex. 29) Calculate the [OH-] for each...

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Example #1 (Ex. 29) Calculate the [OH - ] for each of the following solutions at 25 °C. Identify each as acidic, basic or neutral. a) [H + ] = 1.0 x 10 -7 M b) [H + ] = 6.7 x 10 -4 M c) [H + ] = 1.9 x 10 -11 M d) [H + ] = 2.3 M Also, calculate pH and pOH of each of these solutions ] [H 10 1.0 ] [H K ] [OH -14 w + + - × = = ] -log[H pH + = pH 14 pOH - =
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Example #1 a) [H + ] = 1.0 x 10 -7 M 7 - 7 - -14 w 10 1.0 10 1.0 10 1.0 ] [H K ] [OH × = × × = = + - neutral 7.00 ) 10 -log(1.0 ] -log[H pH -7 = × = = + 7.00 7.00 - 14 pH 14 pOH = = - =
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Example #1 b) [H + ] = 6.7 x 10 -4 M 11 - 4 - -14 w 10 1.5 10 6.7 10 1.0 ] [H K ] [OH × = × × = = + - acidic 3.17 ) 10 -log(6.7 ] -log[H pH -4 = × = = + 10.83 3.17 - 14 pH 14 pOH = = - =
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Example #1 c) [H + ] = 1.9 x 10 -11 M 4 - 11 - -14 w 10 5.2 10 1.9 10 1.0 ] [H K ] [OH × = × × = = + - basic 10.72 ) 10 -log(1.9 ] -log[H pH -11 = × = = + 3.28 10.72 - 14 pH 14 pOH = = - =
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Example #1 d) [H + ] = 2.3 M 15 - -14 w 10 4.3 2.3 10 1.0 ] [H K ] [OH × = × = = + - acidic -0.36 -log(2.3) ] -log[H pH = = = + 14.36 0.36 14 pH 14 pOH = + = - =
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This note was uploaded on 05/11/2008 for the course CHEM 025 taught by Professor Axe during the Spring '08 term at Pacific.

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ch7_ex - Example #1 (Ex. 29) Calculate the [OH-] for each...

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