Solution Manual for Network Management Principles and Practices 2E 2nd Edition

Solution Manual for Network Management Principles and Practices 2E 2nd Edition

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FOR MORE OF THIS COURSE AND ANY OTHER COURSES, TEST BANKS, FINAL EXAMS, AND SOLUTION MANUALS CONTACT US AT [email protected] Chapter 2 Solutions 1. Minimum frame size is the same as the maximum round-trip delay on the LAN. Maximum round-trip delay = (2 x max. I-way propagation delay) + repeater delay = (500 x 5 x 2)/200) + 25 seconds = 50 seconds At 10 Mbps, generated bytes = 50 Mbps x 10 sec = 500 bits ~ 64 bytes, which is the minimum frame size. 2. Maximum round-trip delay is the time it takes a bit to traverse between two farthest end stations. Add to these two traversals of repeater, 1 s each way. Max. R-T delay = (400 /2 x 10 8 ) + 2 = 4 sec. Min. number of bits to detect collision = 4 x 10 -6 x 10 9 = 4000 bits. Minimum bytes is the next higher 2 n bytes is 512 bytes. 3. Choice 1 : Switched Ethernet - Replace regular hub to switched hub. This will increase the maximum capacity to about 6 times. No modifications needed to workstations. Easy to install. Switch the hub and plug the cables into the new hub. Choice 2 : Full duplex - Convert NICs on the 12 workstations and replace the hub to full duplex operation. This requires hardware and configuration changes to the hub and workstations. Will double the capacity. However, this is a dead-end approach. Choice 3 : Convert the network to 100Base-T Fast Ethernet. Need to replace the NICs in the workstations and replace hub for 100BaseT. Increases capacity by ten times. The speed at each workstation increases ten times. Requires 12 NICs for the workstation and a new hub.
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