# on15 - doesnt change, the net work done is zero. (Looks...

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Solution for On-Line Homework 15 Work II Solution to On-Line Homework Problem 15.1(Basic work idea) Problem: You are pushing a fling cabinet across a rough Foor with ±orce v F c y,cab . The cabinet moves a distance d at constant velocity. The total work done on the fling cabinet, i± it is the system, is equal to: Select One o± the ²ollowing: (a) the work done by the ±orce o± ±riction due to the Foor. (b) v F c y,cab · s (c-Answer) zero. Solution Work is the change in the total energy o± a system due to ±orces external to the system. Here there are at least two ±orces, yours and the ±orce o± ±riction, since the speed doesn’t change despite your pushing with a constant ±orce. Since the kinetic energy o± the only thing in your system

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Unformatted text preview: doesnt change, the net work done is zero. (Looks like ric-tion exactly balances your orce, so i you did +W, riction did -W.) 1 point(s) : Total Points for Problem: 1 Points 1 Solution to On-Line Homework Problem 15.2() Problem: Under what condition can you use the equation for aver-age power? Select One of the Following: (a) constant velocity (b) constant position (c) non-uniformly accelerated motion (d-Answer) constant force Solution v F ext must be constant over the span of time for which the average is taken. 1 point(s) : demonstrates under-standing that it must be, or approxi-mates, a constant force. Total Points for Problem: 1 Points 2...
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## on15 - doesnt change, the net work done is zero. (Looks...

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