on24 - ) or x ( t ) = C sin( ωt + φ ) 1 Total Points for...

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Solution for On-Line Homework 24 Periodic Motion I Solution to On-Line Homework Problem 24.1() Problem: What does the position vs. time curve of a simple har- monic oscillator look like? Select One of the Following: (a-Answer) It can be any sinusoidal function, with constants chosen to give the initial conditions. (b) It has to be a sine function if it is position, with constants chosen to give the initial conditions. (c) It has to be a cosine function if it is position, with constants chosen to give the initial conditions. (d) It is a decaying real exponential function, with constants chosen to give the initial conditions. (e) There is no way to tell. Solution A sinusoidal function. The most general form is x ( t ) = A sin ωt + B cos ωt Where the constants A and B are determined by initial conditions ( x 0 and v 0 ). This function can also be expressed as ( C and φ are constants determined by initial condition) x ( t ) = C cos( ωt + φ
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Unformatted text preview: ) or x ( t ) = C sin( ωt + φ ) 1 Total Points for Problem: 1 Points Solution to On-Line Homework Problem 24.2() Problem: What will be the efect oF increasing the strength oF the restoring Force in an oscillating system, iF that is the only change made? Select One oF the ±ollowing: (a) None, you have to change the properties oF the oscillating object to change anything about the motion. (b) The period oF the motion will increase. (c) The amplitude oF the motion will increase. (d) The phase oF the motion will increase. (e-Answer) The Frequency oF the motion will increase. Solution The period oF the given oscillation will decrease when the restoring Force is increased (and iF the restoring Force is de-creased, the period will increase). A stronger spring means the mass will oscillate Faster. Total Points for Problem: 1 Points 2...
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This note was uploaded on 05/04/2008 for the course PHYS 2054 taught by Professor Stewart during the Spring '08 term at Arkansas.

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on24 - ) or x ( t ) = C sin( ωt + φ ) 1 Total Points for...

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