On25 - lar frequency t is the time at which the position is 1 being evaluated and φ is the angular frequency at time t = 0 Solution A is the

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Solution for On-Line Homework 25 Periodic Motion II Solution to On-Line Homework Problem 25.1() Problem: Explain what each term in the following equation for the position of a simple harmonic oscillator represents: x ( t ) = A sin( ωt + φ 0 ) Select One of the Following: (a) A is the displacement, ω is the angular fre- quency, t is the time at which the position is be- ing evaluated, and φ 0 is the initial phase at time t = 0 . (b-Answer) A is the maximum displacement, ω is the angular frequency, t is the time at which the position is being evaluated, and φ 0 is the initial phase at time t = 0 . (c) A is the displacement, ω is the linear frequency, t is the time at which the position is being eval- uated, and φ 0 is the initial phase at time t = 0 . (d) A is the maximum displacement, ω is the linear frequency, t is the time at which the position is being evaluated, and φ 0 is the initial phase at time t = 0 . (e) A is the maximum displacement, ω is the angu-
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Unformatted text preview: lar frequency, t is the time at which the position is 1 being evaluated, and φ is the angular frequency at time t = 0 . Solution A is the amplitude (maximum displacement), ω is the an-gular frequency of oscillation, t is the time at which the position is being evaluated, and φ is the initial phase at time t = 0 . Total Points for Problem: 2 Points Solution to On-Line Homework Problem 25.2() Problem: What quantities does the angular frequency ( ω ) of a simple pedulum depend upon? Select One of the Following: (a) the acceleration due to gravity (b) the mass of the pendulum “bob” (c) the length of the pendulum. (d-Answer) (a) and (c) (e) (a), (b), and (c) Solution The length of the string, and the gravitational acceleration. ω = r g ℓ 2 Total Points for Problem: 2 Points 3...
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This note was uploaded on 05/04/2008 for the course PHYS 2054 taught by Professor Stewart during the Spring '08 term at Arkansas.

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On25 - lar frequency t is the time at which the position is 1 being evaluated and φ is the angular frequency at time t = 0 Solution A is the

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