Chpt7_ExampleProbs_wSols1b

Chpt7_ExampleProbs_wSols1b - Problem 7-6 A particle of mass...

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Problem 7-6 A particle of mass 0.500 kg is shot from P as shown in the figure. The particle has an initial velocity i v G with a horizontal component of 30.0 m/s. The particle rises to a maximum height of 20.0 m above P . Using the law of conservation of energy, determine (a) the vertical component of i v G , (b) the work done by the gravitational force on the particle during its motion from P to B , and (c) the horizontal and the vertical components of the velocity vector when the particle reaches B .
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Problem 7-6 solution 0 = y v level ground 0 unknown ) ! not component horizontal given (only m/s 30 kg 5 . 0 = θ = = y V m i ix v K T 20.0 h a) Determine v iy . Use conservation of energy. We need 2 points, we select points P and T. If we call P initial and T final we get ) ( 2 2 2 1 2 1 h H mg mv E mgH mv E U K E f i f i i i i + + = + = + =
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v i v ix note that 2 2 2 iy ix i V V V + = also 2 2 2 2 2 ix fx fy fx f V V V V V = = + = horizontal velocity doesn’t change for a projectile (Chpt 3)! 0 at max height So use f i E E = v iy wanted) if now determine (could 2 1 2 1 2 1 m/s 8 . 19 2 ) ( 2 2 2 2 θ = = = + + = + + gh V mgh V m mgh mgH mV mgH V V m iy iy ix iy ix (b) Work done by gravity from launch are
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Chpt7_ExampleProbs_wSols1b - Problem 7-6 A particle of mass...

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