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Sample quiz keys - Stat 119 Name 83111121113 1111125...

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Unformatted text preview: Stat 119 Name 83111121113 1111125, chae‘iiem 21 £1 23 11111 11: 1. You cc‘iéeci 11am and 1es1 111e hyeeEhcses Hg 1 1} m @158 Ea : 111 1a (1.58 A PweEue cf (1% is 1111111115111 W’hicé} 111" the feiEewéeg is tree? 1 A @921 cenfiéieece iniervai 1111“ 1:1 wifl 111311111: 1111c the vaéue {1. 50 §$§ A $51111 ccnf1dence ieiewei 1111' :3 W111 1101 1nc111€1e 111s vaéuc 0 50. W“ “M A 911% ceefiéenee interve1 fer 1:1 111111} 11101: 111c§u§e the va111e 1}. 50. gag 1 5 We cannei make a éecisicn using the infermatéen given Aneeeee: 2 We ceice’ieie a $5143 c0111“ fleece iciervei 111117 111 be ((1.112 Q 58}a1_1€1 111311111) 1ee1 the saw fcficwicg: igfi 1’1ng 113% 1:: 3% fiééiyi’ g “EggfiEWng §§ HI :11): 11 41} VS. H: p at 0 411}.er c2111 11%? cecciude: E g Eg 1 . Wcuiri mimics-111031121119 $1? y 91113 $3" ‘ A B. We wcuid rejec1 He 31111 K {1.111. We weuié 11111 1ejec1 H0 31 c1 = 9.115. W’e 111011111 1ejeet H0 a1 (:1 2 6.10.. Aeswer: 3. 131111111: health cfficiais beiéeve 111111 911% cf chfidme have beee vacciea‘ied agaiest measies A 11111110111 survey cf medicai records at many schools 3,011,155 the country faced 111111 amcng mere 1112111 13 969 chiidren 01113; 89.11% heé been vaccinated. A 51311311111311 emcee-ted a We Sided hygcthesis test 3111} ceiculateé e 11v eigeg of 0 {311 V1111" h of 1e fe11cw111g siatemems 15 ccrrect‘? ' """ 1‘1 $1., A. Teere 1s statisticeéiy $1g111ficen‘i: evidence of a sucstantzei change 111 the percent 01 chfidren vaccinated ' B. There 1s 1101 sfiiisficafly Significant evidceee 01" a cheege 111 Ehe percent of 6111;111:311 vaccinated. C. There is statistically significen‘i eviéence cf 3 13111111 ge 111 the cement of chiid1‘e11 1) vaccinated, ané 11113 outcome is else practicafiy significant. There 13 siafisficaiiy significant evieenee of a change 111 {he percent of chiidree vaccinated, 11111 this outcome 13 cf no practice} sigmficance. Aeswer: A1. 111 e hyeefiesés 1631:, if “we rejec1 The 111111 11111111111111, what type cf c1101 cceié have been made? , . 11' we 1eject the 111111 hypothesis, we wenid 11111 have made e11 errer. T1136 i Tyee H . Beth Type I or Type 11 me 1303311116 Aeewee: The iifefime (fie Exams} ef e certain iyee ef Eégjhé: we is keewn ie be eemeiéy éisieéeeieéi. we seek we were used te ebteie a 93% eeefieeeee éetewelé estimate ef the tree mean Eifeiime ef the iigh‘i bulbs. The eeefieenee ieterveé was eaieuieied ‘ie ee {3 335%,9, E3165. 1'} S. The meeefae‘eeee effigie gee ef Eight beies eieime eke: e23; Easea ee eveeege, 143% beers, Es gheee etatésééeei evéeeeee iee: {his eieém is weeng‘? Test eke eéeee, using the eeefiéeeee intervai fiivee. E. Edeeeify me eeéi em} eéeeeeefive emeeheses. fige gee MW e fifiem EE. \éeke en geeeeriete decisiee éveag e eee seeeeeee Eestéfieefiee ef eeeeg éeeieéee. flew eee fie?“ Ee “Eee %?5e :54” ee {figifigé “fig? {$353 ew,§§E LgfiEefi ee Effie?" See: eve awe? §é§§§ he; 1 er" the feiiewmg Seeiemeees éeeeefibes e Tyee ii eeree ie the peebfieea? Making the decisiee the? the mean Eifeeme of file iighfii beles '25 E499 eezee whee, ie feet file fight beibs do ee‘i 3:15:31“: average 0f MEGS heme. eE‘Makieg ehe deeisiee :hee eke Eigi‘e ewes de eet East an average ef 34% heme when, ée fact, they do 135% an avenge ef 149% hours. e) Making the eeeisiee aha: me mean ééfefime of the fight Eeées £5; Eéiéfi heere when; fie feet, the light eeibs de last ae average ef 146% hours. dEMakieg the deeieiee éhet the mean iifetiiee of ”the fight buEbs is :30: 3.40%} hoers when, fie fem:a the iig‘n‘i eeibs fie nee Ease ee evea‘age 0f Mfifi beers. Aeeeer: fie answee greemseie_ ES- Eek With increases? concern over maéemining edeqeei‘e cash flew, a beiédees‘ sepeiy company wishes $0 esiimate the average amount weed is it by its credit custemers. For {his perpese, 25 of the company’s ieeeiees are randomiy sampied and are {Send to pessess an aeerage eredii baianee 0f $32§fi wife a standaré Seviatien of $355. Assume {he pepifiatéee of ereéit beieeee $03315 is éiseihu‘ied nemeflyv {E a: $3? high? ‘3 mg S ‘33 Egfi 7. The mite} mine needed 1e eaiceiete e 95% eeefidenee mien/re? £3: a} L96 c} 2.167 d) 2576 e) 132%} ' fit 3% Anewee: an? 8. Using fiae eritéeei veiee aeeves, eeleeieie e 93% eeefieeeee .énEereeE eseimete fee file parameter ef meeeeeé. 3m; #3? 2; eee {WE eié 6. § 3 NEEWEZ’? {Eeeefiee age} Aeewer: 3% fiw fefifiwiflg iafarmafiéaa is: mswe; gmfiemg gum E: is maimed that iha avarage age {if Eifegaafis £33 La 59333, is 25% years; A raseaz‘she: 323mm that ihe avemga age is; greasy fizan 2% years. Size Sew-gig em SE13 9%” 3% Eifeguards and finés flags samgie 233% is: E38 24%“? years. Suggege ii is kaewga $23? $336 aggs {QEEGW a fiermai fiisizéim‘zéefi, Wfifii a gfiméafien stanéaré éeyiatien 93“ 2 years. gm! 0:; 2 gg $3. Siam figs mg: and afiemative hypaéhegssy fifiigfi fiaffify 19. Candacfi a iesfi of £313 hygatheses idemifiaé abeve; 3 E. Caficaiaig {ha test statisiic: fig? :3?” j: 2 ‘ Egg ii. Caicufigfie tile safieswnéing p~vaiue ?5 art; a 3%: ER Make a staiis’iiizai dscisian {aging a Esvei 9f significame cf {1%}! @flygém E $5; 3% M?% E m int rpmt yam dfi gésion in the camera ofihe probiem w m? fiffig’” i:§ma& £1 %3 aamg ggaw éfim ; if H. Which affix .u iowéflg staiements corset: y interpi’eis the p—Value for this test: a) fl is the probafiéliiy of ebserving a gavpaiatim mean a}: ieagt as iarge 33 24 in a gmpée whose mean is 24.? b) it is the probfihiiity thg papuiaiien mean is 30%; equai i9 24. c} it is the pmhawiizy of ebgerving a samgée 21363:: at Eeast as smaji 3.3 24‘? in a ,.____ popuiation whose mean: is 24, _ It is She pmbabiiity of efisgwing a 53mph mega at Eeasi as iarge as 24.? in a pepuiafion Mime mean is 24 E2 15m esfimaie is neeéfié of the mean acreaga 9f farms in afimzée Cafiafiég Haw iarge a sampfie @ff aims is naeéad m (Ede? £02“ a 95% cenfiésnce imam? is have a margin of firm; 0%" 2% gems? An estim ed an iafisfi“ {am} ameage in this pmvmce is 45 Use the feiiewing infermeeiee fer ereeiems 13-19 The eompesitien of the earth’s erreesehere may have eirenged ever time. Te Er}; to ééseeeer the nature of the atmesphere Eeeg age, we can exemiee the gas in bubbles inside ancient ameer. Measurements or: a raedem sample at" amber from the 'iate eretaeeees era gave the fofiewieg ameeets of ni’erogee. Beee tiiés sameie seggest that the weer: amount er" nitregen ie the air dering the eretaeeees era was different {rem tee present mean garment of 65.5? w 63.4 65.6 64.4 63.3 $4.8 64.5 69.8 79.1 SM} 33. identify appropriete net} are? alternative hypetheses. eé§~§ 14. Calcuiate the test statistic b. .. M. _ .:: m i. eel 15. Calcuiate the corresponding puvaéee. égfisg ££§e§£§esf§i§ ’Qfi é. §wg§e§ E6. Make a statistical deersion using a .GE ievel of signifieaece. Justify Eeur decisierr. Peeeisse e st rs 3 7 interpret your decision 11'] the context of the probiem Segfi er get” gee éefifiefi: e? sergee re res r meek. e? 58.1fihe reset: yeu e rained was a mistake whet type ef error wouid yea have made? 19. Suppose we wish e; reerease the pewer for the above test. One way t0 ée this weeid be to: A. Increase the probaeifiity £2? a Type ii error. Increase the erebahiiity of a, Type 3 error. . increase the pwakue of the test. D. it is not pessiele to eheege the grower 0‘? a test. Answer: ...
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