_022 - Solution for Homework 23 Optical Systems Solution to...

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Unformatted text preview: Solution for Homework 23 Optical Systems Solution to Homework Problem 23.1(Identify Virtual Image) Problem: Select the one of the following that is NOT a virtual image. Select One of the Following: (a) Image seen in mirror. (b) Image seen in magnifying glass. (c) Image seen through curved glass at aquarium. (d-Answer) Movie at the theater. Solution An image that can be projected is not virtual, so the movie you see on a movie screen is a real image. Total Points for Problem: 3 Points Solution to Homework Problem 23.2(Crossed Polarizers) Problem: Unpolarized sunlight with intensity 1000 W m 2 is incident on two polarizers, whose transmission axes make an angle of 30 . Calculate the intensity of the transmitted light from the second polarizer. Select One of the Following: (a) 750W / m 2 (b) 430W / m 2 (c-Answer) 375W / m 2 (d) (e) Toby Solution The first polarizer decreases the intensity of the light by 2 , I 1 = I / 2 . The second polarizer further reduces the intensity according to Maluss law, I 2 = I 1 cos 2 30 = ( I / 2) cos 2 30 = (1000 W m 2 / 2) cos 2 30 = 375 W m 2 Total Points for Problem: 3 Points Solution to Homework Problem 23.3(Dropping Coin in Tank) Problem: You are playing a game where you drop a coin into a water tank and try to land it on a target. You often find this game at fast food places as part of a fundraiser. The sides of the tank are flat and the target is 6in from the side of the tank. Your eye is 9in from the side of the tank. Water has index of refraction of 4 / 3 . If you drop the coin accurately and it falls straight down to the location where the target appears to be, how far are you off? Does the coin fall in front or behind the target as you look at it? Select One of the Following: 1 (a) . 75in behind the target. (b) 1 . 5in behind the target. (c) . 75in in front of the target. (d-Answer) 1 . 5in in front of the target. Solution The object distance is 6in . The radius of curvature is infinity. The incident index n i = 4 3 and the transmitted index is n t = 1 . Subsitute into the single interface equation, n i s + n t s = n t- n i r = 0 4 / 3 6in + 1 s = 0 s =- 18 4 in =- 4 . 5in So the coin falls 1 . 5in in front of the target. Total Points for Problem: 3 Points Solution to Homework Problem 23.4(Two Lens Problem) Problem: A converging lens of focal length 12cm and a diverging lens of focal length- 15cm are separated by 55cm . An object is placed 22cm to the left of the converging lens. Compute the distance (with correct sign) the final image forms from the diverging lens....
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This note was uploaded on 05/04/2008 for the course PHYS 2074 taught by Professor Stewart during the Spring '08 term at Arkansas.

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_022 - Solution for Homework 23 Optical Systems Solution to...

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