mt1sol - Math 218(Spring 2008 Solutions to MT1 TA Wei Lin...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Math 218 (Spring 2008) Solutions to MT1 TA: Wei Lin 1. (a) Simply add up each row and column: 1 problem 2 problems 3 problems Total Brand A 20 12 3 35 Brand B 15 7 3 25 Brand C 10 6 4 20 Total 45 25 10 80 (b) P (Brand A and 1 problem) = 20 / 80 = 1 / 4. (c) The number of cars being Brand A or having 1 problem is the sum of all the numbers in the “Brand A” row and the “1 problem” column, that is, 20 + 12 + 3 + 15 + 10 = 60. Hence, P (Brand A or 1 problem) = 60 / 80 = 3 / 4. Another method: P (Brand A or 1 problem) = P (Brand A) + P (1 problem)- P (Brand A and 1 problem) = 35 / 80 + 45 / 80- 20 / 80 = (35 + 45- 20) / 80 = 3 / 4. (d) P (1 problem | Brand A) = # { 1 problem and Brand A } / # { Brand A } = 20 / 35 = 4 / 7. Another method: P (1 problem | Brand A) = P (1 problem and Brand A) /P (Brand A) = (20 / 80) / (35 / 80) = 20 / 35 = 4 / 7. (e) P (Brand A | 1 problem) = # { Brand A and 1 problem } / # { 1 problem } = 20 / 45 = 4 / 9....
View Full Document

{[ snackBarMessage ]}

Page1 / 2

mt1sol - Math 218(Spring 2008 Solutions to MT1 TA Wei Lin...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online