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Exam2spring2000 - EXAM #2 Prineiptes ef Genetics (Biel...

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Unformatted text preview: EXAM #2 Prineiptes ef Genetics (Biel 2153}, Larkin Spring Zflflfl Remember in fill in year name and ID number en the answer sheet! Cheese the best answer fer eaeh questien ley filling in the apprepriate spaee en year answer sheet. There are 33 attestiens. l. Cressing ever eeeurs during: a} the mitetie prephase "eeffl nteiesis. h‘t t'neielie prephase I. e} meietie prephase Ll. I d} meietie anaphase 11. L“ I ' l e thi-ee wha'e “Ear-Ideltdfly Elihu.” EMMA—B D ll e} nene el" the sense. 2. The arrew in the Figure In the right is petttting :lt.‘ a] n pelytene ehrerneseme, bl tnitntie spindle. e) u ehittsina. d} :1 eueleelus. et an X ehrumesemu. Quesliens 3 thrnugh 8 refer tn the results ef the feIlewing test eress inyelying three genes: In dragen flies. the reeessiye trait yeltew hedy is eenueiled hy the y allele ['5’ results in the EIL‘tth'ttll l'tlilL'li hedy}. The reeessiye trait sitert wings is eentrelled hy the 5' allele t_'.s' results in the dermal leng wings}. The reeessiye trait mange eyes is eeetrelled hy the 0 allele te' results In the net-mat red eyes}. A phenetypieally wild—type dregenfly hetereeygees fer alleles at all three genes is eresseel with a fly that is phenetypieally yellow—heeled. shed-winged. and erange~eyed Pregeny with the phenetypes git'ert helew result item this tress: Bride Wings r‘-' ef d[gg gnflies hlaelt Jen g erange 331 hlaek sheet erange 59 yellew len g red 6? yellew shert erange e hlaelt shert red _ 43 black leng red 1 5 yellew in lull-ta erange 44 yellew shert red 3;? 100D tetal 3. If these three genes asserted independently. we weuid have espeeted: a) aheut 125 dragenflies in eaeh ef the eight phenerypie classes. h) sheet SCH] black teng ersnge dragenflies and EDD yellew shert red dragenflies, and rte ether classes e) tnere than eight pltenerypie eIasses. d} feur phenetypie classes. e} nene ef the sense. 4. Whieh ef the fellewing is the eerreet genen'pe ef the phenerypieafly wild—type parent. disregarding ereler ef the genes en the ehretneseeee‘? a} y+ 3" e‘i" y se l3} }‘ 5‘ (if .5‘ r)" e] y 5" eTy‘ .r e d) y‘ s" efys n' e) eannet he determined item the infennatien given. 5. 1t‘t’hat is the correetgene order for these three genes? a} y — .r — o bl .r —}=— o e} y —- o — s :1} none of the above. 6. Which of the following is a correct map distance [in chi} between a pair of genes? {lift—3:13.17. h} in — o = 21.5 e} o —— s = 14.? a} t: —— e1 = no.3 e) none ofthe above. S. a second cross is performed int'oltting the some three dragonfin genes. This cross is identical to the first cross, except that the phenotypiealiy wild—type parent is heteroaygous fora paracentric inversion that includes all three genes Lt. s. and o]. How would this affect the proportion of phenottr ically oiled-to tweaeammaagaamegmnmmga Lillie—Latte J straatafie / re -Epl Jamey" n} lnerease. h} Decrease. c} Stay the same. d} No 1eia'ole offspring ofonjr genotype tttould he produced. Questions 9 and lil refer to the following genetic map: to eat so are I A——E~—r——~—C 9. From the testcross A B Cfa h e :t a h cfa h c. 1it-hat proportion of individuals 1would have the A h C phenotype? a} Efl'i't's b) lfi'fih c} 2% d) [9% e} [3.5% F! in 5 1D. From the cross given in question 9, what proportion of individuals would have the we phenotype? a) 20% h} 19% e} 10% d} 5‘31: e] 4% I l. A chromosome transloeation is the result of: at) removing DNA from a single ehromaome. h) adding DNA to a single ehromsome. e} nondisjunction. d} exchange of portions of two different chromosomes. e} changing the order of DNA in a chromosome without adding or removing anything. 11. The trait “big ears“ is a dominant trait CDWfiDI‘Jj‘ found in politicians. lConsider the iotlowing pedigree. which shows affected individuais with big eats (titled titties] and blood-type (A. B. AB. or 0}. Us: a x1 test to determine if there is sufficient evidence to cone-[ode that the genes for "big ears" and blond type are limited. Which of the foliowing statements is true? II Ei—rl o o so 1 2 in I . Bo Bo- :T-"ti. Criticdi Vain: 3} x: =d.25. d.f.. the genes we iinked. h} x] =’.25. d.i.r the genes are iinJ-ted. o 11 = 4o. 2 d.f.. the genes sIe not set-ea. c012: 4.13. 1 d.t'.. the genes are linked. e] x2 = 4.1]. i d.t'.. the genes are not linked p—-l-J 3.5-1.1 53"]: 15.13 9.453 11.03”? 11.593 HEEL" 13.53? 15.919 W 15.3%]? 15 24.996 3'] 31.410 35 31552 3'3 43.?73 “E-JEa-eted Ell'lL'iE'S. from R. A. Fisher and Yates. 19-13. Ettrtllstl'mi' Effie: f‘r Edi-.133}. .figrtt'ul'turdl' mu." .Jtiee' :ei Restlrrt'l': Dli'l't'l' ant‘. Boyd. Lend: n. 13. The bars below the diagram of e partieuie: horned chromosome indicate the EJEIT. of the chromosome tomoved by two different deficiencies, Djlit and DIE. defining thsee different regions of the Chromosome. regions 1.2. and 3. it! I I q | es e— aim—Wus bit-t , " I I‘ u L L _ WW 139:3?” Ting-em Rest-row. Another trait often found in pfiitioieng. “red nose”, mags to this general regioo of this chromosome. This trait is recessive. la pedigrees segregating for both the “ted nose“ trait and life, individuals heterozygous for Dfifii have never been found to have a red nose. In pedigees segregating for both the “red nose" trait and DIE: individuals heterozygous for D}? have often been found to have a red nose, time; Both Dfidi and 9.3319 lethal when homozygous, so the red nose trait is never due to a homozygous Bf. In Which region is the “red nose" gene most iii-eels to be located? a} Region 1 13} Region 2 C} Region 3 E1} The gene is not located within any of the L-‘tree regions. 14. What is the name of the method that could be used to test whether an individual with a red nose: w heterozygous for one ofthe Dgt'mentionecl in Q. iii? a] Transformation. la) Pulse—labeling. c} Karyotyping d] Replication. cl Chisarnnta. 3.3 15. Hybrids hetn-‘ccn different plant species often results in new species of planm that are: a) polyploid. h} aneuploid. cl trisomic. d} deleted. e} inverted. lo. .ftrt photograph of an X-Tilljr' diffraction pattern important in determining the structure of Dis-n was taken 133-: at James 1‘t‘t'atsnn. h] Francis Crick. cl Rosalind Franklin. cl} Erwin Citargail. ct Oswaldnvery. ll". The single strand at the right indicates a molecule of a] DNA. 5‘ ACE-T 3' h) DNA. 5' TGCA 3‘ c} DNA. 5' Gr’sC'l' 3' :1} RNA. 5’ ACGU 3' with. the sequence .‘I'H. cl Rota. s' noon 3' o gap/la...- I_—.-l._::I—r|_'H: vu-AHLJJ LI KEN it l-l- sfl s- J... J _- I - o .-. 13. Upon analyzing a sample ofDl‘Jr-‘s. you find that 20?: ofthe u l n i nucleotides are adenine (A). What percentage are cytosine tCJ? o a) Edit: .4. p. 3&an l3) Bflfie C'--||'-D—t.'r-:. (gr-'1‘.“ all. __ c} 4D'Erifi .l. l ' D 'I " 5" a} secs e] son i .' I G a. r H ' 19. Prokaryotic chromosomes such as that of E. can are generally: D'l—D—LT“: pas") a} packaged hycoihng around nucleosomes. 5" I “Hi h) linear. e] circular and supercoiled. .3. g; d) larger than the chromosomes of enhaqotcs. H e} found in the nucleus. EU. The arrow in the Figure to the right points to: a} A DNA strand with no associated protein. h} A stretched—out strand of DNA wrapped around nucleosomes {it} run Fiber}. (:3 A St] am chromatin I'ther consisting ofa coil of nucleosornes Wltl’l DNA wrapped around them. ill The chromosome scaffold. * e} A prokaryotic chromosome. Sin-so 1"1_ art j 3'.- 1-le' I'Llll'r‘" ' lt‘l‘ W5? IL‘:.IHI!I" 'nfh'a'dfu'f'gl -"-' QUESTIUNS 21 TBA REFER TO THE STAGES OF DNA REPLICATIDH LISTED BELOW: a} Stage 1: Rotation of DNA ahead of the replication fork. hi Stage ll: Formation of single—stranded template. c] Stage Ill: Leading strand synthesis. :1} Stage W: Lagging strand synthesis. Stages may he used more than once! El. in which stage is DNA prirnase int-oiyed’.J 22. in which stage is DNA heliease inyolyed? 23. in which stage is RNA involved? 24. DNA polymerase 11] is involved in which singers)" a) Stage ll only. h] Stage ill only. c} Stage 1V only. d} Stages ll and Ill. e} Stages Lil and I‘m-i. ’15. The 5‘—:: 3' exonoclease of DNA polymerase I is required for: a] adding nucleotides during DNA synthesis. b] removing RNA daring lagging strand synthesis. I3} proofreading to ensure accuracy. d} ligation of nicks in the DNA. e) unwinding the DNA. 26. la the diagram at the right. the arrow points to: al the 5' end of the leading strand. h} the 5‘ end of the lagging strand. c} the 3' end of the leading strand. :1) the 3‘ end of the lagging strand. e} the origin of replication. 2T. Eultaryotic chromosomes have: a} no origin of replication 1}} a single origin of replication. c} multiple origins of replication. d) no DitazaI-ti fragments during Lhier replication. 28. 1Which of the following is n_ot needed for Hansel‘iptiofl'? a] Nucleotide Lri phosphates. h} A DNA template. c) n. prirner. dl RNA polymerase. cl Promoter sequences. 19. 1ii‘t'hich ofthe following is n_ot a true stateroan about genes”? a} Euharyotic chromosomes contain multiple genes. is} Ettkt‘tfi'filic genes often contain introns. c} Genes me not altered by changes made to their protein product. at All genes encode proteins. is N; .u N ..-—si- t. .~.rT-.vi.i--. mm r —m— _ C—"t— MEL—- 1 t t + l -—| -'.o -— '5-1‘ —- 1 3 3t}. In the. diagram oFa c.1.tki11'}'otit: gene shown aho'i'e. the arrow indicates: at the location ofthc start of transcription. l'tl the'f'r-‘tTa'i hos cl the —ltt sequence. :1} the CHAT boa. c] the position ot'the 5' cap. 31. ll'thc sequence indicated by the arrow in Q. 36 is changed by mutation: at the pre-otRNa‘i will he transcribed, hut ii will not he spliced. h} the rot-ERA will he transcribed. but it will not be translated ct transcription of the I'D—RNA will no! he initiated. dl transcription of the otRNa‘t will not he terrotnated. e't DNA repticniin will not occttr. 32. snRNFis are involved in what process'.j at Transcription. Isl Splicing of pt'c-mRNr's. ct Translation. d] Addition of the 5" cap. e] Additjpn of the polytint tail. 33. The diagram below shows processes taking place in: a} a proltarpote. To) the eakaryotic nucleus. cl eakaryotic cytoplasm. d] downtown Baton Rouge on a Saturday night. ...
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Exam2spring2000 - EXAM #2 Prineiptes ef Genetics (Biel...

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