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Exam3Spring2000

Exam3Spring2000 - EXAM#3 Principles of Genetics{Biol 2153...

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Unformatted text preview: EXAM #3 Principles of Genetics {Biol 2153), Lat-kin Spring Zflflt} Remember to fill in your name and ID number on the answer sheet! Choose the best answer for each question by filling in the appropriate space on your answer sheet. There are 33 questions. Game-Hg. Lois- +LLLIE' om lat-sf- Peifi- L 1. Which ofthe structures at below is an amino acid? a} bl lemon ox ‘oa I t DH. H c) to H H H‘%"é—-EH H i 2. Ribosomes are assembled a} in the nucleolus. b) on the rough ER. e] on the smooth ER. d] in the cytoplasm. e] in the Golgi apparatus. 3. All prokargotic proteins are initated with a} a 5‘ cap. is) methionine. c) forrnyl—methionine. d) tyrosine. e} a stop codon. 4. In a charged LENA. the amino acid is attached to which part oftitc LENA? a} Anticodon. b) 'Coclon. c} Inosine. d) 5' end. e} Tend. 5. In the diagram to the right, what will be the nest-t step in translation? a} peptide bond formation. b} charging of a tRNf-t. e) binding of another tRNA to the a site d) transloeation of the ribosome e) release of the ribosome from the mRNA. In questions ti through 9, match the molecule to the stages of translation in the list helonr in which it is involved. A step may be used once, or not at eff. Stages: a} charging o'ftRNA h} locating conect AUG cotton and imitating translation c) elongation of polypeptide chain and translocation of rihosome d} release of rihosome from mRNA ti. GTP is involved in 'i. ATP is involved in E. Aminoacyl—tRNFt synthase is involved in . 9. The Sliine-Delgarno sequence is involved in it}. There are six different codons for the amino acid scrine. This is an example ofwhat property of the genetic codc'ir a} lClrticr. h) chencracy. c} Universality. d} Punctuation. c) Chaos. 1 l. a point mutation that changes a codon so the triplet codes for a different amino acid is called a a} nonsense mutation. h) missensc mutation. c) fratncshift mutation. d} transition. e} insertion. i2. Inosine can base pair with: a} G in] Ft c} C d} Goran e) A.l.l.orC 13. When a suppressor tRNA suppresses a nonsense mutation. the resulting protein a] contains one more amino acid than WT. h] contains one less amino acid than WT. c} is always restored to the W1” amino acid sequence. :1} may have a different amino acid at the site of the nonsense codon. 34. Which of the following base substitutions is a transversion? Questions 15, Ill and 1’? refer to the hypothetical eukaryotic gene shown below. «Only one strand of the double-stranded DNA is shown, this coding [or nontemplate} strand. The start of transcription is indicated by the arrow at +1, and the splicejurtction sequences are underlined. Assume that transcription stops at the last base given. +1 ii 5 . —and:c;GantstscanTGGGtsccgfla'racTTgficcaaoa't‘rnamcT-s . W Pt 15. What polypeptide would be translated from the mRNA of this gene? a) Mctfilofilyfisnfilyfida‘t’al b) MetGlyProGinVai c} Lysr‘ilahtletGlyProGInVal d] MelGlyPro c) MetValAlahlaLeu id. Tltc region of the mRNfit corresponding to the region of the gene marl-ted lay the bracket {l} labeled A is called: a} UHF tn S'LJTR c} B’UTR d) coding region c} MCr’tT IT. r't +3 I'ramesltii‘t mutation occurs at the point indicated by arrow B. Which ofthc following is a true statement about the effect of the resulting mutation on the polypeptide produced, relative to WT? a] There will be a stop codon at the site of thc frantcshit't. b} The mutant polypeptide will have a completely different sequence downstream of the frameslu'ft. c) The mutant polypeptide will have one less amino acid. d) The mutant polypeptide will have one more amino acid. Ill. The Lederberg‘s experiment using streptomycinrrcsistartce in bacteria showed that: a} tautomcrs are a common cause of mutations- b) that chemicals can cause mutations. c} that X-rays cause mutations. d} mutations occur randomly. rather than adaptively. c) mutations are rate. 19. Tautomeric forms of the bases cause mutations because: a) The tautomer chemically modifies other bases. b) Tautomers cause chromosome breaks. c} Tautome rs cause nus—pairing of bases during DNA replication. d} Tautomers cause frameshifts. e) Tautomers act as nonsense suppressors. 212}. Which of the following is a common kind of DNA damage caused by LEV. light? a) Chromosome breaks. b} Insertions. e) Deletions. d} Thymine dimers. e} Tautomers. '21. Which of the following would be an example of a neomorphie mutation? a} A mutation reducing the activity of an enzyme. b] A mutation eliminating the activity of an enzyme. of; A mutation allowing an enzyme to use a new substrate. d} A mutation increasing the activity of an enzyme. 22. Which of the following is not required for repair of UN. damage to DNA by the nucleotide excision pathway? a) DHAligasc. b) DNA Polymerase l. c) DNA hellcase. d} UvrABC complex 23. WT lizards of a particular type are purple. There are three mutations available that block different steps in the biosynthesis of the purple pigment. From the phenotypes of single and double mutants listed below. what is the probable order ofbiochtuieal intermediates in the pathway? urgent Qatarefltzatd a EIEET‘I. b' blue c' yellow ab green a'c‘ green be blue a) bluc—ayellow—agreen—apurple h) yellow—ngreenwablue—apurple c} yellow—srblue—agreen—npurple d) green—ablue—ayellow—spurpte 24. For the example given in Q. 23, which gene encodes the first enzyme in the pigment biosynthesis pathway? a) gene a b} geneb c} gene c 25. Four independent mutations of E. coil that are unable to grow without added adenine were examined in all possible air and rrrrnrheteroaygotes. All eis heterozygotes were able to grow. The results for the trons heterozygotes is given below. A “4-“ indicates growth of the heteroaygote and a "Cl” indicates failure to grow. Mutant 1 E 3 4 1 D + + D E U + + 3 l} + 4 D How many different genes are these four mutations likely to represent? a) 1 b} 2 c} it tildl 26. You have discovered a new white—eyed mutant in Drosophr'ln. When you cross this fly with a WT fly. the F1 have white eyes. When this fly is crossed with a fly homozygous for the well-known recessive white—eyed mutation w. the F1 are also white‘eyed. What can you conclude about the relationship between your new mutation and the w mutation? a) Both mutations are in the same gene. b} The two mutations are in different genes. of} There are at least dues genes that can mutate to a white—eyed phenotype. r1} Nothing. because the new mutation is dominant. 2?. The Figure to the right shows a bacterial cell infected by a virus. Based on the structures visible in the cell. what stage of the infection cycle is shown? a) Immediately after infection. b) Early in infection. c} Late in infection. 23. Where does the membrane surrounding the Hill:ir capsid come from? a) Plasma membrane ofeell. b} Synthesized by virus. c} Rough ER. d) Smooth ER. e} Golgi apparatus. 29. 1|t‘r'l'ticl't of the following is not part of the HIV life cycle? a} Attachment of virus to CD4 protein on cell surface. b) Reverse transcription of RNA. c) Integration of viral DNA into host genome. d] Packaging ofviral DNA into capsid. c] Budding of virus particles from cell surface. 3D. What is the function of restriction endonucleascs in a bacterial cell‘? it} DNA repair. b) Ligation of DNA. c} Defense against viruses. d) Antibiotic resistance. c} Construct recombinant DNA. 31. You have discovered a new mutation that causes a human disease. The results of a Northern blot and a Westem blot probed with appropriate probes to detect mENA and protein expressed from the gene are shown below. Which type of mutation in the gene is most likely to have caused the disease phenotype? Nani-gr». lilac it} e were E let-{— “T Nil-urger'i _T HUI-pm? . a} Missense mutation. LEE" L“ "if" b} Nonsense mutatoa near the N—temtinus of encoded protein. c) Promoter mutation. d) Splice junction mutation. sealer gull" 32. The purpose of including-an antihiotie-resistauee gene on a plasmid eloning veetor is: a} To proteet the eel] against viruses. h} To prevent the eell from digesting itself with restrietion enzymes. e) To allow eell's that earrv the plasmid to he identified. d) To eause mutations. e) To ligate DINA together. 33. Whieh of the following is no; a true statement about transposons'? a) Transposons ean insert into new piaees in the DNA. h} At least 5% of the human genome is eornposed of transposons. e} Transposons ean eause mutations. d] All transposons use reverse hanseriptase when the}I move. TEBLE 13.1 Tim Gunulh! Emil?" sfir " ' rue-m. mr‘lf-I a-mr ”11'. a?“ . , . 1..- - -.i'r+-.--._ f; 4* ‘Jfln #r“ ..: E 1-H} [- Phi \11' in} :11 15%,..- 'u' E a" " +'-'l‘.-_ _ r? J; {lemma}? Third {3'} letter Hrs: {5'} Letter [iniu'atnri 'Each triplet nutleatide seq-smug or cadm “3321's to the Wealth sequence in mHPf-fi. that DNA? that SpEcifiE5 [he mcarpurafinn of the hinted amim and a: pamephde chem. lermmaL-qn. ...
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