EE450_HW_3_solutions

EE450_HW_3_solutions - EE450 Computer Networks Fall 2007 Homework#3 Solutions(100 points Textbook Problems Chapter 1 Problems#28 Answer(10 points(a

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EE450: Computer Networks, Fall 2007 Homework #3, Solutions (100 points) Textbook Problems: Chapter 1: Problems #28, Answer: (10 points) (a) 640 × 480 × 3 × 30 bytes/sec = 26.4 MB/sec (b) 160 × 120 × 1 × 5 = 96,000 bytes/sec = 94KB/sec (c) 650MB/75min = 8.7 MB/min = 148 KB/sec (d) 8 ×10 ×72× 72 pixels = 414,720 bits = 51,840 bytes. At 14,400 bits/sec, this would take 28.8 seconds (ignoring overhead for framing and acknowledgments). Problems #30, Answer: (15 points) (a) A file server needs lots of peak bandwidth. Latency is relevant only if it dominates bandwidth; jitter and average bandwidth are inconsequential. No lost data is acceptable, but without real-time requirements we can simply retransmit lost data. (b) A print server needs less bandwidth than a file server (unless images are extremely large). We may be willing to accept higher latency than (a), also. (c) A file server is a digital library of a sort, but in general the world wide web gets along reasonably well with much less peak bandwidth than most file servers provide. (d) For instrumentmonitoringwe don’t care about latency or jitter. If data were
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This note was uploaded on 05/05/2008 for the course EE 450 taught by Professor Zahid during the Fall '06 term at USC.

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EE450_HW_3_solutions - EE450 Computer Networks Fall 2007 Homework#3 Solutions(100 points Textbook Problems Chapter 1 Problems#28 Answer(10 points(a

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