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120_ch.13_review - function s(t =-16t 2 112t 240 models the...

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Mat120 Chapter 13 Review name___________________________________ Solve the equation by the square root property. If possible, simplify radicals or rationalize denominators. Express imaginary solutions in the form a + bi. 1) (x + 2) 2 = 20 Solve the quadratic equation by completing the square. 2) x 2 + 14x + 34 = 0 Solve the quadratic equation by using the quadratic formula. 3) x 2 + x + 5 = 0 Use the discriminant to determine whether the following equation has solutions that are two rational solutions; two irrational solutions; one real solution; or two imaginary solutions. 4) 2x 2 + 6x + 5 = 0 Write a quadratic equation in standard form with the given solution set. 5) { - 4, 10} 6) { - 10i, 10i} Sketch the graph of the quadratic function. Identify the vertex, intercepts, and the equation for the axis of symmetry. 7) f(x) = - (x - 1) 2 + 4 x -10 -5 5 10 y 10 5 -5 -10 1
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Determine whether the given quadratic function has a minimum value or maximum value. Then find the coordinates of the minimum or maximum point. 8) f(x) = x 2 + 2x - 2 9) f(x) = - 4x 2 + 8x Solve. 10) An object is propelled vertically upward from the top of a 240 - foot building. The
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Unformatted text preview: function s(t) = -16t 2 + 112t + 240 models the ball's height above the ground, s(t), in feet, t seconds after it was thrown. After how many seconds does the object reach its maximum height? Round to the nearest tenth of a second if necessary. Solve the equation by making an appropriate substitution. 11) x 2/3- 6x 1/3 + 5 = 12) x-2 + x-1- 6 = 2 Answer Key Testname: 120_CH.13_REVIEW 1) {-2 + 2 5 ,-2- 2 5 } 2) {-7- 15 ,-7 + 15 } 3) {-1 ± i 19 2 } 4) Two imaginary solutions 5) x 2- 6x- 40 = 6) x 2 + 100 = 7) x-10-5 5 10 y 10 5-5-10 Vertex: (1, 4) x-intercepts: (-1, 0) and (3, 0) y-intercept: (0, 3) axis of symmetry: x = 1 8) minimum; (- 1,- 3) 9) maximum; (1, 4) 10) 3.5 seconds 11) {1, 125} 12) {- 1 3 , 1 2 } 3...
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