7e5D9umGHg0y_1210016418_jwk572

7e5D9umGHg0y_1210016418_jwk572 - homework 12 KIM, JI Due:...

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Unformatted text preview: homework 12 KIM, JI Due: Nov 21 2007, 4:00 am 1 Question 1, chap 19, sect 1. part 1 of 2 10 points An air bubble originating from an under- water diver has a radius of 3 mm at some depth h . When the bubble reaches the surface of the water, it has a radius of 5 . 3 mm. The acceleration of gravity is 9 . 8 m / s 2 . Assuming the temperature of the air in the bubble remains constant, determine the depth of the diver. Correct answer: 46 . 5215 m (tolerance 1 %). Explanation: Let : = 1000 kg / m 3 , g = 9 . 8 m / s 2 , P atm = 101000 Pa , R 1 = 5 . 3 mm = 0 . 0053 m , and R 2 = 3 mm = 0 . 003 m . From the ideal gas law P V = nRT = constant , so P 1 V 1 = P 2 V 2 P 1 P 2 = V 2 V 1 P atm P atm + g h = 4 3 R 3 2 4 3 R 3 1 = R 3 2 R 3 1 R 3 1 P atm = R 3 2 ( P atm + g h ) h = P atm ( R 3 1- R 3 2 ) g R 3 2 = 101000 Pa (1000 kg / m 3 )(9 . 8 m / s 2 ) (0 . 0053 m) 3- (0 . 003 m) 3 (0 . 003 m) 3 = 46 . 5215 m . Question 2, chap 19, sect 1. part 2 of 2 10 points Determine the absolute pressure at this depth. Correct answer: 556 . 91 kPa (tolerance 1 %). Explanation: The absolute pressure is P = P atm + g h = 1 kPa 1000 Pa bracketleftBig 101000 Pa + ( 1000 kg / m 3 )( 9 . 8 m / s 2 ) (46 . 5215 m) bracketrightBig = 556 . 91 kPa . Question 3, chap 19, sect 1. part 1 of 1 10 points One mole of an ideal gas at 0 C is held at a constant volume of 99 L. Find the change in pressure if the tempera- ture increases by 69 C. Correct answer: 0 . 0572079 atm (tolerance 1 %)....
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7e5D9umGHg0y_1210016418_jwk572 - homework 12 KIM, JI Due:...

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