E4lt5Z87F2r4_1210016614_jwk572

# E4lt5Z87F2r4_1210016614_jwk572 - . 91 μ F capacitor?...

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inclasstest 04 – KIM, JI – Due: Feb 11 2008, 1:00 pm 1 Question 1, chap -1, sect -1. part 1 of 1 1 points This is a question for showing your atten- dance. Please choose the correct answer be- low, or you will lose 25% of this weekly test. 1. This is the correct answer. correct 2. This is the wrong answer. Explanation: It is correct because the choice does not lie. Question 2, chap 26, sect 2. part 1 of 1 3 points An 8 . 91 μ F capacitor charged to 43 V and a 3 . 91 μ F capacitor charged to 36 V are con- nected to each other, with the two positive plates connected and the two negative plates connected. What is the ±nal potential di²erence across the 3
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Unformatted text preview: . 91 μ F capacitor? Correct answer: 40 . 8651. Explanation: Let : C 1 = 8 . 91 μ F , V 1 = 43 V , C 2 = 3 . 91 μ F , and V 2 = 36 V . From the formula Q = C V , the initial charges on the capacitors are Q 1 = C 1 V 1 and Q 2 = C 2 V 2 and the total charge is simply Q = Q 1 + Q 2 . When the two capacitors are connected (in parallel), the total charge is then Q ′ = C eq V = ( C 1 + C 2 ) V . But charge is conserved so Q = Q ′ , and C 1 V 1 + C 2 V 2 = ( C 1 + C 2 ) V V = C 1 V 1 + C 2 V 2 C 1 + C 2 = (8 . 91 μ F) (43 V) + (3 . 91 μ F) (36 V) 8 . 91 μ F + 3 . 91 μ F = 40 . 8651 V ....
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## This note was uploaded on 05/05/2008 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas at Austin.

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