LW9sqgPmR7yF_1210016745_jwk572

# LW9sqgPmR7yF_1210016745_jwk572 - speed of 6 03 m s 14 7 Ω...

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inclasstest 07 – KIM, JI – Due: Mar 24 2008, 1:00 pm 1 Question 1, chap -1, sect -1. part 1 of 1 1 points This is a question for showing your atten- dance. Please choose the correct answer be- low, or you will lose 25% of this weekly test. 1. This is the wrong answer. 2. This is the correct answer. correct Explanation: It is correct because the choice does not lie. Question 2, chap 31, sect 1. part 1 of 1 3 points Find the power dissipated in the 14 . 7 Ω resis- tor in the ±gure. The 1 . 03 T uniform magnetic ±eld is directed into the plane of the circuit and the 47 . 9 cm long conductor moves at a
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Unformatted text preview: speed of 6 . 03 m / s. 14 . 7 Ω 1 . 03 T 1 . 03 T I 47 9 cm 6 . 03 m / s Find the power dissipated in the resistor. Correct answer: 602 . 092. Explanation: Let : B = 1 . 03 T , ℓ = 47 . 9 cm , R = 14 . 7 Ω , and v = 6 . 03 m / s , Motional emf: E = B ℓ v . Power dissipated in resistor: P = E 2 R . The motional emf induced in the moving conductor is E = B · ℓ · v = (1 . 03 T)(0 . 479 m)(6 . 03 m / s) = 2 . 97502 V The power dissipated in the resistor is P = E 2 R = (2 . 97502 V) 2 14 . 7 Ω = 602 . 092 mW ....
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## This note was uploaded on 05/05/2008 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas.

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