Unformatted text preview: speed of 6 . 03 m / s. 14 . 7 Ω 1 . 03 T 1 . 03 T I 47 9 cm 6 . 03 m / s Find the power dissipated in the resistor. Correct answer: 602 . 092. Explanation: Let : B = 1 . 03 T , ℓ = 47 . 9 cm , R = 14 . 7 Ω , and v = 6 . 03 m / s , Motional emf: E = B ℓ v . Power dissipated in resistor: P = E 2 R . The motional emf induced in the moving conductor is E = B · ℓ · v = (1 . 03 T)(0 . 479 m)(6 . 03 m / s) = 2 . 97502 V The power dissipated in the resistor is P = E 2 R = (2 . 97502 V) 2 14 . 7 Ω = 602 . 092 mW ....
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This note was uploaded on 05/05/2008 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas.
 Spring '08
 Turner
 Physics

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