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Unformatted text preview: Mathematics 105, Spring 2004 M. Christ Final Exam Solutions (selecta) 1 (2e) True or false: If K R is a compact set of Lebesgue measure zero, and if f : R R is a homeomorphism (that is, f is continous and invertible, and f 1 is also continuous), then  f ( K )  = 0. Solution. Like all the true/false questions, this is false. Take K to be the Cantor set C [0 , 1] which is defined by successively deleting middle thirds of intervals. C = n =0 C n where C n is a disjoint union of 2 n (particular) intervals of length 3 n . Consider the piecewise linear function f n which is constant on each interval in the complement of C n , and has constant slope equal to 3 n / 2 n on each of the intervals comprising C n . It can be shown that the sequence f n converges uniformly as n to a limiting function f , which is necessarily continuous. Consider the function g ( x ) = f ( x ) + x . Then g is strictly increasing and is continuous, so is a bijection from R to R , and also has a continuous inverse. Since g (0) = 0 and g (1) = 2, g maps [0 , 1] bijectively to [0 , 2]. [0 , 1] \ C is a countable disjoint union of intervals I , the sum of whose lengths equals  [0 , 1] \ C = 1 0 = 1. On each of those intervals I , g ( x ) = x plus a constant, so each I is mapped to an interval of length  I  . Their images are disjoint, so  g ([0 , 1] \ C )  = I  I  = 1. Since g ( C ) = [0 , 2] \ ( g ([0 , 1] \ C ) ) , it follows that  g ( C )  = 2 1 = 1 > 0. (4a) Let ( E, A , ) be a measure space and for each j = 1 , 2 , let A j A . Suppose that j =1 ( A j ) is finite. Let B be the set of all points x E which belong to infinitely many of the sets A j . Show that ( B ) = 0....
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This note was uploaded on 05/07/2008 for the course MATH 105 taught by Professor Michaelchrist during the Spring '04 term at University of California, Berkeley.
 Spring '04
 MichaelChrist
 Math

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