MP29- Newton's Third Law

MP29- Newton's Third Law - MasteringPhysics: Assignment...

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3/2/08 4:54 PM MasteringPhysics: Assignment Print View Page 1 of 6 http://session.masteringphysics.com/myct/assignmentPrint?assignmentID=1114150 [ Print View ] PHYS 2211 ABCDE Spring 08 MP29: Newton's Third Law Due at 11:59pm on Thursday, February 28, 2008 View Grading Details Block on an Incline Adjacent to a Wall A wedge with an inclination of angle rests next to a wall. A block of mass is sliding down the plane, as shown. There is no friction between the wedge and the block or between the wedge and the horizontal surface. Part A Find the magnitude, , of the sum of all forces acting on the block. Hint A.1 Direction of the net force on the block Hint not displayed Part A.2 Determine the forces acting on the block Part not displayed Part A.3 Find the magnitude of the force acting along the direction of motion Consider a coordinate system with the x direction pointing down the incline and the y direction perpendicular to the incline. In these coordinates, what is , the component of the block's weight in the x direction? Express in terms of , , and . ANSWER: = "Normal," in this context, is a synonym for "perpendicular." The normal force has no component in the direction of the block's motion (down the incline). Express in terms of and , along with any necessary constants. ANSWER: = Part B Find the magnitude, , of the force that the wall exerts on the wedge. Hint B.1 The force between the wall and the wedge Hint not displayed Part B.2 Find the normal force between the block and the wedge What is the magnitude, , of the normal (contact) force between the block and the wedge? (You might have computed this already while answering Part A.) Express in terms of , , and . ANSWER: = Part B.3 Find the horizontal component of the normal force In the previous hint you found the magnitude of the normal force between the block and the wedge. What is the magnitude, , of the horizontal component of this normal force?
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3/2/08 4:54 PM MasteringPhysics: Assignment Print View Page 2 of 6 http://session.masteringphysics.com/myct/assignmentPrint?assignmentID=1114150 Express in terms of and . ANSWER: = Express in terms of and , along with any necessary constants. ANSWER: = Your answer to Part B could be expressed as either or . In either form, we see that as gets very small or as approaches 90 degrees ( radians), the contact force between the wall and the wedge goes to zero. This is what we should expect; in the first limit ( small), the block is accelerating very slowly, and all horizontal forces are small. In the second limit ( about 90 degrees), the block simply falls vertically and exerts no horizontal force on the wedge. PSS 8.1: Dashing up the Slope Learning Goal: To practice Problem-Solving Strategy 8.1 for problems involving the dynamics of an interacting systems of objects. A girl of mass
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MP29- Newton's Third Law - MasteringPhysics: Assignment...

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