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Unformatted text preview: Solutions for Quiz #1 Problem 1: Use nodal analysis to find the voltage V o in the following circuit: 12V 6 4A 6A 12 +- 9V 4- +- + V O We put the ground node at the bottom, and then the left hand node has a value of -12V and the right hand node has a value of 9V, so there is only one unknown node, which is V o . 12V 6 4A 6A 12 +- 9V 4- +- + V O-12V +9V So we can write the KCL equation for node V o as follows:- 12- V o 6 = V o 4 + 4 and we can directly solve this equation for V o . We multiply both sides by 12:- 24- 2 V o = 3 V o + 48- 72 = 5 V o so V o =- 72 5 V olts 1 Problem 2: (a) Find the Thevenin equivalent for the following circuit, to the left of the terminals A-B. Draw the Thevenin equivalent circuit. (b) Use the Thevenin equivalent circuit to determine the power dissipated in the 3 Ω resistor on the right. + _ 6V 1 2 + V X-- + V X 2 A B- 3 + V o First we want to find the open circuit voltage: + _ 6V 1 2 + V X-- + V X 2 A B- + V oc The current from the 6V source has nowhere to go except around the left hand mesh. So we haveThe current from the 6V source has nowhere to go except around the left hand mesh....
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This note was uploaded on 05/07/2008 for the course ECE 53 taught by Professor Cheng during the Spring '08 term at UCSD.
- Spring '08