CHEM 2212 EXAM 4

CHEM 2212 EXAM 4 - K5 NAME first Elfii‘.‘ aweee3 last...

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Unformatted text preview: K5 NAME first Elfii‘.‘ aweee3§ last, Be sure to read each question carefiilly. Partial credit wili be assigned where appropriate. To receive full credit you must answer the question completely. {July answers written in EXAM 4 NDWHIBER 28, zoo? SCORE pen and in the'spaces or boxes provided will be graded. I. (41) {Johns} Complete the following reactions by providing the necessary starting materisfls), reagent{s), andfor major product{s}. CN'HHCN 3. CHEMISTRY 2212 I catch3 6. Q :1 m— 2 — 1. CH3MgBr, Etflfl 2. Hg'o'T"—_' 1 :l “m“ ' - oxidizing agent 2 l I @‘CDUH such as KMnU4 i or (Tr-33, 1130+ SDCli,_beuz-:ne heat HI Br _ /\/‘(\ 1. Na‘CNa’ ethanol =2. menefixer 3. H30+ U \TJ‘KC] + ethar .0 dm [CH3C0120 0H UH H+ I . 2. H30+ 1. Lime... , H30“ (E: 0 Mat fir 2, DEC 1 . LiA 1H4, ether 2. H30 CH3CH=2CH2CHC=_N J CH 2CH 3 0H ? OH + CHECDGH 3 2. (14 points) Ptiuvide the. IUPAC names for the fullnwing compounds. '3. H0 D D | HECZCH—CEN \\ ,GCHECHg I NH2 0 ||_ NH— CHE'CHIICH- 3- .. . '3 {IE pointgj'Writfi a; mmpIete,.-$wpwi$: .mflehamsm far the failpwing panvmfifin using the WI. .V"'i.‘d-31'rfi.-. W W 't'na"'1isn'1. MAE:- HCI V10 3 5.- 1-1. (IE 11:1111sj W111: 11 1111111111111: smpwis: 111::11111111111 1:1. .111: 1111111111111: :11111111_si:11- 111111: 111': 11111-11111. 41111111r E11111:11.1111. H1111; 1111111:- -J1'y111:'11_1ysis 11111111111311 1111 1:11:11111'1111111 wdfkup 1.-'-1~;1'1111'1 1' 11311 H .. ' -._ " 1 + Q: NHI 1.11121 . C 9H + “H4 'fi' “5. [H1 minufi Write; synth'efi'c s’gqfienée to 'fifiéémblifli thi: fqlldfingflansfnnnfififin that ”as am inelude-anmteras-au intmdiate; Shcrwall magnntmnd all-intermefiiaxastmctlmes. (12 11311131111312 asymthotlo soquonoa 13.312111113311511 thg. foflongi. trafioformaoon 16312-3133: 1.15: an}; 1131135531151. inorgamo maggots and an};- oarhon reagents- oonmining two whons or I'm Show 321 wage-111:3 321.21 all mtormodmto 521312311123 -‘CH1.UDI¢H2¢HIS _.,GH3 ...
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