Physx141MPch1sol

Physx141MPch1sol - 1.24. (b) (c) (d) 1 m 20 ft = 20 ( ft )...

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1.24. Solve: (a) () 1 m 20 ft 20 ft 7.0 m 3 ft  ==   (b) 5 1 km 1000 m 60 miles 60(miles) 1.0 10 m 0.6 miles 1 km × (c) 1 m/s 60 mph 60(mph) 30 m/s 2 mph (d) 2 1 cm 10 m 8 in 8(in) 0.16 m 1/2 in 1 cm 1.26. Solve: (a) We need kg/m 3 . There are 100 cm in 1 m. If we multiply by 3 3 100 cm (1) 1 m = we do not change the size of the quantity, but only the number in terms of the new unit. Thus, the mass density of aluminum is 3 33 kg 100 cm kg 2.7 10 2.7 10 cm 1 m m ×= × (b) Likewise, the mass density of alcohol is 3 g 100 cm 1 kg kg 0.81 810 cm 1 m 1000 g m = 1.46. Solve: A car starts coasting at an initial speed of 30.0 m/s up a 10 ° incline. 230 m up the incline the road levels out to a flat road and the car continues coasting at a reduced speed along the road.
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This note was uploaded on 05/05/2008 for the course PHYS 141 taught by Professor Staff during the Spring '06 term at Cal Poly.

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