# 13493 686926 0287 ln 300 092013 kjkgk 1s2 gen 092013

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Unformatted text preview: 0.287 ln ( 300 ) = 0.92013 kJ/kgK 1s2 gen = 0.92013 1500 = 0.5569 kJ/kgK o o k k-1 1.4 544.83 For the second process we get P2 = P1 exp[ (sT2 sT1)/R ] = 100 exp( 8.13493 6.86926 ) = 8227 kPa 0.287 1w2 = (u2 u1) = (759.19 214.36) = 544.83 kJ/kg o o 2 [20 Points] A steady state heat pump definition of COP COP = HP = QH / W = 1 + QL / W W = QL / (HP 1) = 5000 / 1.5 = 3333 kW . . . . . . QL QH . C.V. H.P Entropy equation: 0 = T T + Sgen L H QH QL 8333 5000 Sgen = T T = 185 + 273 85 + 273 = 4.23 kW/K H L 3 [30 Points] CV Tank Continiuty Eq.: m2 m1 = mi = m2 0 = m2 . . . . . Energy Eq.: m2u2 m1u1 = m2u2 = mihi + 1Q2 1W2 = mihi + 1Q2 2 Tbl. B.1.3: v2 = 0.42492 m3/kg ; u2 = 2642.91 kJ/kg; i. Tbl. B.1.3: hi = 2855.37 kJ/kg 0.005 m2 = Vtank / v2 = 0.42492 = 0.011767 kg 1Q2 = m2u2 mihi = 0.011767 (2642.91 2855.37) = 2.5 kJ If 1Q2 = 0 then u2 = hi = 2855.37 & 500 kPa T2 = 332.9oC...
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