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hw9key - t> 200 s μ 4 200 2 10 s s-= × 4 4 4 4 1 10 2...

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1 HW9Key First, 0 < t < 200 , we have two deferential equations: ( I1 is the current go through the inductor and I2 is the current go through resistor. s μ 1 2 1 2 10 dI L I R dt I I = + = Solve these equations( with initial condition: I1=0 when t = 0), we will get: 4 4 1 10 1 1 10 2 10 10 10 10 10 10 R t t L R t t L I e e I e e - - × - - × = - = - = =
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2 HW9Key Second,
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Unformatted text preview: t > 200 ( ) s μ 4 200 2 10 s s-= × ( ) 4 4 4 4 1 10 2 10 1 10 1 2 [email protected](200 ) 1 10 10 10 9 R t t L s t I I I e e e e--- × × ×- ×- × = = × =-× = 3 HW9Key Energy conserve 2 6 2 2 2 3 1 1 1 10 40 0.4( ) 2 2 10 10 CV CV LI I A L--× × = ⇒ = = = ×...
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