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Unformatted text preview: Miller, Kierste – Homework 12 – Due: Apr 17 2007, 3:00 am – Inst: Gary Berg 1 This printout should have 22 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points If a n , b n , and c n satisfy the inequalities < b n ≤ c n ≤ a n , for all n , what can we say about the series ( A ) : ∞ X n = 1 a n , ( B ) : ∞ X n = 1 b n if we know that the series ( C ) : ∞ X n = 1 c n is convergent but know nothing else about a n and b n ? 1. ( A ) converges , ( B ) converges 2. ( A ) converges , ( B ) need not converge 3. ( A ) converges , ( B ) diverges 4. ( A ) diverges , ( B ) converges 5. ( A ) diverges , ( B ) diverges 6. ( A ) need not converge , ( B ) converges correct Explanation: Let’s try applying the Comparison Test: (i) if < b n ≤ c n , X n c n converges , then the Comparison Test applies and says that X b n converges; (ii) while if < c n ≤ a n , X n c n converges , then the Comparison Test is inconclusive be cause X a n could converge, but it could di verge  we can’t say precisely without further restrictions on a n . Consequently, what we can say is ( A ) need not converge , ( B ) converges . keywords: Comparison Test, conceptual 002 (part 1 of 1) 10 points Determine whether the series ∞ X n = 1 tan 1 n 2 + n 5 converges or diverges. 1. series is divergent 2. series is convergent correct Explanation: We apply the Limit Comparison Test with a n = tan 1 n 2 + n 5 , b n = 1 n 5 . For lim n →∞ n 5 ‡ tan 1 n 2 + n 5 · = lim n →∞ tan 1 n = π 2 . Thus the given series ∞ X n = 1 tan 1 n 2 + n 5 is convergent if and only if the series ∞ X n = 1 1 n 5 Miller, Kierste – Homework 12 – Due: Apr 17 2007, 3:00 am – Inst: Gary Berg 2 is convergent. But by the pseries test, this last series converges because p = 5 > 1. Con sequently, the given series is convergent . keywords: 003 (part 1 of 1) 10 points Determine whether the series ∞ X n = 1 2 + n + n 2 √ 4 + n 2 + n 6 converges or diverges. 1. series is convergent 2. series is divergent correct Explanation: We apply the Limit Comparison Test with a n = 2 + n + n 2 √ 4 + n 2 + n 6 , b n = 1 n . For then lim n →∞ a n b n = lim n →∞ 2 n + n 2 + n 3 √ 4 + n 2 + n 6 = lim n →∞ 2 n 2 + 1 n + 1 r 4 n 6 + 1 n 4 + 1 = 1 > . Thus the given series ∞ X n = 1 2 + n + n 2 √ 4 + n 2 + n 6 converges if and only if the series ∞ X n = 1 1 n converges. But, by the pseries test (or be cause the harmonic series diverges), this last series diverges because p = 1. Consequently, the series is divergent . keywords: 004 (part 1 of 1) 10 points Which of the following series converge(s)?...
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This note was uploaded on 05/08/2008 for the course M 408 L taught by Professor Cepparo during the Spring '08 term at University of Texas.
 Spring '08
 Cepparo

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