Solution7 - Digital Electronics Answer Sheet 7 1. Bit...

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Digital Electronics Answer Sheet 7 1. Bit Pattern Unsigned Signed 0101 5 5 1101 13 13-16=-3 1111 16-1=15 -1 00100000 32 32 11011111 255-32=223 -1-3 =-33 01111110 128-2=126 126 10000000 128 -128 2. The basic reason is that the range of numbers is asymmetrically distributed about zero. For an 8 bit system, say, the range is -128 to +127. It is therefore impossible to represent (-1 x -128). 3. & 4. You can find the answers in any textbook. 5. The answer to this question will not be presented here since 7 segment display decoders will be studied further in the Electrical Laboratory. 6. a) −− 2 t o 2 2 NN which needs N+1 bits. b) () 22 2 1 N to which needs 2N bits. Note that it nearly fits into 2N-1 bits whose range extends to 21 N . 7. To invert the number, we must interchange segments a and d, b and e, and c and f. We need a standard 7-segment decoder followed by multiplexers to do the switching. See figure 1. When ENABLE is high, the display will be turned off; if it is connected to a square wave, the duty cycle will control the brightness of the display. This
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Solution7 - Digital Electronics Answer Sheet 7 1. Bit...

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