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Unformatted text preview: y ), therefore RR D x 2 y 3 dA = 0 since D is also symmetric in y (i.e. ( x,y ) D ( x,y ) D ). Finally, RR D 4 dA = 8 since this integral is the volume of a cylinder of radius 2 and height 4. Therefore RR D ( x 2 tan( x ) + y 3 + 4) dA = 8 ....
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This note was uploaded on 05/09/2008 for the course MATH 2130 taught by Professor Dorais during the Spring '08 term at Cornell University (Engineering School).
 Spring '08
 DORAIS
 Math, Calculus

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