quiz_07A - ≤ sin( x + y ) ≤ 1 for ( x,y ) ∈ R ....

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Math 213 — Quiz 7 Name Solution 1. Show that 0 RR R sin( x + y ) dA 1 where R = [0 , 1] × [0 , 1]. When ( x,y ) R , i.e. 0 x 1 and 0 y 1, we have 0 x + y 2. Since 0 sin( z ) 1 when 0 z π and π 2, it follows that 0
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Unformatted text preview: ≤ sin( x + y ) ≤ 1 for ( x,y ) ∈ R . Therefore, 0 = ZZ R dA ≤ ZZ R sin( x + y ) dA ≤ ZZ R 1 dA = 1 as claimed....
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This note was uploaded on 05/09/2008 for the course MATH 2130 taught by Professor Dorais during the Spring '08 term at Cornell University (Engineering School).

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