phys6a lab 4

phys6a lab 4 - to fix this problem except to either create...

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Physics 6AL (TA Benson) Lab 4: Rotational Dynamics Derek Pan 1.Torque=r*F*sin(90) Force=Tension, sin(90)=1 Therefore, torque=r*T 4.a=h/t^2 5.The larger the radius is, faster an object on the turntable will move. They are directly proportional. Therefore, the claim is valid. 6. Torque angular acc (m/s^2) 0.000019 5 0.867 0.000075 1.667 0.000161 5 2.4 0.000460 3 4.1 0.000642 4 4.77 0.000901 7 5.73 Torque=Inertia*angular acceleration Inertia=Torque/Angular acceleration Therefore, average inertia = 0.0000898 (kg*m^2) Sources of Error: The time in seconds could be off due to human error in recording. It could be fixed if the time could be mechanically recorded. Also, the pulley is obviously not perfect. Friction is a factor that was not considered. There is no real way
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Unformatted text preview: to fix this problem except to either create a perfect frictionless pulley or calculate the friction constant and factor in the amount of work has in the equation. Data: Height (m) Mass (kg) Time (s) Acc (m/s^2) angular acc (m/s^2) Tension (N) Torque (kg*m^3) /s^2 0.87 0.05 5.78 0.026 0.867 0.000000065 0.000019 5 0.87 0.1 4.16 0.05 1.667 0.00000025 0.000075 0.87 0.1495 3.47 0.072 2.4 5.382E-07 0.000161 5 0.87 0.2495 2.65 0.123 4.1 1.53443E-06 0.000460 3 0.87 0.2995 2.47 0.143 4.77 2.14143E-06 0.000642 4 0.87 0.3495 2.25 0.172 5.73 3.0057E-06 0.000901 7...
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phys6a lab 4 - to fix this problem except to either create...

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