phys6b lab 1

# Phys6b lab 1 - log10(y = log10(4 log10(x^3 After reducing the right side it is obvious that the original equation(y=4x^3 gives the antilog of the y

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Derek Pan TA: Benson Physics 6B Lab 1: Pendulum 1.1: mass (g) period (s) 8.5 1.968 96.5 2.064 301.5 2.044 1.2 No 1.3 mass: 96.5g angle (degrees) time(s) 1 time(s) 2 15 2.064 2.07 10 2.05 2.056 5 2.018 2.021 1.4 No 1.5 mass: 96.5 g angle (degrees) time(s) 1 time(s) 2 25 2.162 2.21 40 2.218 2.15 1.6 No 1.7 angle: 10 degrees mass:96.5 g length (cm) time(s) 1 time(s) 2 80 1.72 1.726 60 1.544 1.562 40 1.268 1.294 1.8 Yes 2.1 Yes there is a positively correlated linear relationship. 3.1 Yes, the relationship is linear. Slope=0.1111

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x y=3x log(x) log(y ) 1 3 0 0.477 121 2 6 0.30103 0.778 151 3 9 0.477121 0.954 243 4 12 0.60206 1.079 181 5 15 0.69897 1.176 091 3.2 y-intercept=0.477121 Inverse-log(0.477121)=1.29152 3.3 Yes. Slope =3 x y=4x^3 log(x) log(y) 1 4 0 0.60206 2 32 0.30103 1.50515 3 108 0.477121 2.03342 4 4 256 0.60206 2.40824 5 500 0.69897 2.69897 3.4 y-intercept=0.60206 Antilog=4 3.5 log10(y) = log10(4x^3)
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Unformatted text preview: log10(y) = log10(4) + log10(x^3) After reducing the right side, it is obvious that the original equation (y=4x^3) gives the antilog of the y intercept (4). 3.6 log10(y) = log10(4) + log10(x^3) log10(y) = log10(4) + 3log10(x) After reducing the right side, it is obvious that the exponent (3) is the slope of the graph. 3.7 The slope would be 1/3. 4.1 slope = 0.483047 4.2 y-intercept=-0.71135 4.3 Period=2pi(length/a)b log(Period)=log(2pi(length/a)b) log(period)=log(2)+log(pi)+blog(length/a) Variable a is dependent upon length. The value of a =0.71135 4.4 b=0.483047 4.5 length=((period^2)xg)/(4pi^2) 5.1 The rod has a longer period....
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## This note was uploaded on 04/15/2009 for the course PHYS physba taught by Professor Geller during the Spring '09 term at UCSB.

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Phys6b lab 1 - log10(y = log10(4 log10(x^3 After reducing the right side it is obvious that the original equation(y=4x^3 gives the antilog of the y

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