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Unformatted text preview: 20Vx(2.6kohms/4.3kohms)=12.09V Ohms law holds because the two individual voltages add up to the total circuit current. 3.1 Voltage (V) Current (mA) 9.98 4.59 V=IR 9.98=(0.00459) R R=2174 ohms 3.2) new current = 9.1 mA (0.0091 A) 9.98V=(0.0091A)R R=1096.7 ohms The current increased. 3.3) As resistance decreases, current flow increases. 3.4)Current again increased. This time, to 13.73 mA 3.5) Again, as resistance decreases, and source voltage stays the same, then current flow will increase. 3.6) 1/2.2k+1/3.1k+1/6.7k=R R=1.08kohms 3.7) 18Vx2.2kohms/(2.2kohms+1.7kohms+2.6kohms)=6.09V 18Vx1.7kohms/(2.2kohms+1.7kohms+2.6kohms)=4.71V 18Vx6.7kohms/(2.2kohms+1.7kohms+2.6kohms)=18.6V I(2200ohms)=18V I=0.0082A I(1700ohms)=18V I=0.0106A I(2600ohms)=18V I=0.0069A...
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