CHAPTER 11
11.1
v
O
=
v
S
1
M
Ω
1
M
Ω+
5
k
Ω
1000
(
)
1
k
Ω
1
k
Ω+
0.5
Ω

A
v
=
v
O
v
S
=
990
or
59.9
dB
i
S
=
v
S
1
M
Ω+
5
k
Ω
and
i
O
=
990
v
S
1
k
Ω

A
i
=
i
O
i
S
=
990
1000
10
6
=
9.9
x
10
5
or
120
dB
A
P
=
A
v
A
i
=
990 9.9
x
10
5
(
)
=
9.8
x
10
8
or
89.9
dB

v
S
=
v
O
A
V
=
5
V
990
=
5.05
mV
11.2
v
O
=
v
S
5
k
Ω
5
k
Ω +
5
k
Ω
31.6
(
)
1
k
Ω
1
k
Ω +
1
k
Ω
and A
v
=
v
O
v
S
=
7.91
or 18.0 dB
v
s
=
v
O
A
v
=
10
V
7.91
=
1.27
V
Since R
out
has the same value as R
L
, the power
dissipated in R
out
is also 0.5W.
The power dissipated in R
id
will be
P
I
=
V
id
2
2
R
id
=
V
S
2
⎛
⎝
⎜
⎞
⎠
⎟
2
2
R
id
=
V
S
2
8
R
id
where
V
S
=
V
O
7.91
and V
O
=
2 0.5
W
(
)
1000
Ω
(
)
=
31.6
V
P
I
=
4
2
8 5000
(
)
=
0.4
mW
.
The total power dissipated in the amplifier is
P = 500mW + 0.4mW = 500 mW.
11.3
0.99
mV
≥
1
mV
R
id
R
id
+
50
k
Ω
⇒
R
id
≥
4.95
M
Ω
11.4
I
o
=
2 100
W
(
)
50
Ω
=
2
A
and
I
o
2
R
out
2
≤
5W
or
R
out
≤
2.5
Ω
11.5
v
id
=
v
O
A
=
10
V
10
5
=
0.1
mV

10
V
A
≤
10
−
6
V
requires A
≥
10
7
or 140 dB
11.6
v
id
=
v
O
A
=
15
V
10
6
=
15
µ
V

15
V
A
≤
10
−
6
V
requires
A
≥
15
x
10
6
or 144
dB

i
+
=
15
µ
V
1
M
Ω
=
15
pA
111
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