# Microelectronic Circuit Design

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CHAPTER 11 11.1 v O = v S 1 M 1 M Ω+ 5 k 1000 ( ) 1 k 1 k Ω+ 0.5 | A v = v O v S = 990 or 59.9 dB i S = v S 1 M Ω+ 5 k and i O = 990 v S 1 k | A i = i O i S = 990 1000 10 6 = 9.9 x 10 5 or 120 dB A P = A v A i = 990 9.9 x 10 5 ( ) = 9.8 x 10 8 or 89.9 dB | v S = v O A V = 5 V 990 = 5.05 mV 11.2 v O = v S 5 k 5 k Ω + 5 k 31.6 ( ) 1 k 1 k Ω + 1 k and A v = v O v S = 7.91 or 18.0 dB v s = v O A v = 10 V 7.91 = 1.27 V Since R out has the same value as R L , the power dissipated in R out is also 0.5W. The power dissipated in R id will be P I = V id 2 2 R id = V S 2 2 2 R id = V S 2 8 R id where V S = V O 7.91 and V O = 2 0.5 W ( ) 1000 ( ) = 31.6 V P I = 4 2 8 5000 ( ) = 0.4 mW . The total power dissipated in the amplifier is P = 500mW + 0.4mW = 500 mW. 11.3 0.99 mV 1 mV R id R id + 50 k R id 4.95 M 11.4 I o = 2 100 W ( ) 50 = 2 A and I o 2 R out 2 5W or R out 2.5 11.5 v id = v O A = 10 V 10 5 = 0.1 mV | 10 V A 10 6 V requires A 10 7 or 140 dB 11.6 v id = v O A = 15 V 10 6 = 15 µ V | 15 V A 10 6 V requires A 15 x 10 6 or 144 dB | i + = 15 µ V 1 M = 15 pA 11-1

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