Chapter16

Microelectronic Circuit Design

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Unformatted text preview: CHAPTER 16 16.1 A v s ( ) = 50 s 2 s + 2 ( ) s + 30 ( ) | A mid = 50 | F L s ( ) = s 2 s + 2 ( ) s + 30 ( ) | Poles: -2,-30 | Zeros: 0,0 Yes, s = 30 | A v s ( ) 50 s s + 30 ( ) | L 30 rad s | f L = L 2 30 2 = 4.77 Hz f L = 1 2 30 2 + 2 2 2 0 ( ) 2 2 0 ( ) 2 = 4.79 Hz A v j ( ) = 50 2 2 + 2 2 2 + 30 2 | MATLAB : f L = 4.80 Hz 16.2 A v s ( ) = 400 s 2 2 s 2 + 1400 s + 100,000 = 200 s 2 s + 619 ( ) s + 80.8 ( ) | A mid = 200 | F L s ( ) = s 2 s + 619 ( ) s + 80.8 ( ) Poles: -619,-80.8 rad s | Zeros: 0, 0 | Yes, a 5:1 split is sufficient | s = 619 A v s ( ) 200 s s + 619 ( ) | L 619 rad s | f L 619 2 = 98.5 Hz f L 1 2 80.8 2 + 619 2 2 0 ( ) 2 2 0 ( ) 2 = 99.4 Hz A v j ( ) = 200 2 2 + 80.8 2 2 + 619 2 | MATLAB: 100 H z 16.3 A v s ( ) = 150 s s + 15 ( ) s + 12 ( ) s + 20 ( ) | A mid = 150 | F L s ( ) = s s + 15 ( ) s + 12 ( ) s + 20 ( ) Poles: -12, -20 rad s | Zeros: 0, -15 rad s | N o, the poles and zeros are closely spaced. f L 1 2 12 2 + 20 2 2 0 ( ) 2 2 15 ( ) 2 = 1.54 Hz A v j ( ) = 150 2 + 15 2 2 + 12 2 2 + 20 2 | MATLAB: f L = 2.72 H z | L = 17.1 rad s Note that L =16.1 rad/s does not satisfy the assumption used to obtain Eq. (16.15), and the estimate using Eq. (16.15) is rather poor. 03/09/2007 Richard C. Jaeger and Travis N. Blalock - 3/10/07 17-1 16.4 A v s ( ) = 9 x 10 11 3 s 2 + 3.3 x 10 5 s + 3 x 10 9 = 3 x 10 11 ( ) 10 4 ( ) 10 5 ( ) s 10 4 + 1 s 10 5 + 1 = 300 s 10 4 + 1 s 10 5 + 1 A mid = 300 | F H s ( ) = 1 s 10 4 + 1 s 10 5 + 1 Poles: -10 4 ,-10 5 rad s | Yes: A v s ( ) 300 s 10 4 + 1 | H 10 4 rad s | f H 10 4 2 = 1.59 kHz f H 1 2 1 10 4 2 + 1 10 5 2 2 1 2 2 1 2 1 = 1.58 kHz A v j ( ) = 3 x 10 11 2 + 10 4 ( ) 2 2 + 10 5 ( ) 2 | MATLAB: f H = 1.58 k H z 16.5 A v s ( ) = 3 x 10 9 ( ) 1 + s 3 x 10 9 10 7 1 + s 10 7 1 + s 10 9 = 300 1 + s 2 x 10 9 1 + s 10 7 1 + s 10 9 A mid = 300 | F H s ( ) = 1 + s 3 x 10 9 1 + s 10 7 1 + s 10 9 | Poles: -10 7 , -10 9 Zeros: -3 x 10 9 , Yes: A v s ( ) 300 1 + s 10 7 | H 10 7 rad s | f H 10 4 2 = 1.59 MHz f H = 1 2 1 10 7 2 + 1 10 9 2 2 1 3 x 10 9 2 2 1 2 1 = 1.59 MHz A v j ( ) = 2 x 10 9 2 + 3 x 10 9 ( ) 2 2 + 10 7 ( )...
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This note was uploaded on 03/05/2008 for the course EE 307 taught by Professor Braun during the Spring '08 term at Cal Poly.

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Chapter16 - CHAPTER 16 16.1 A v s ( ) = 50 s 2 s + 2 ( ) s...

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