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Chapter17

# Microelectronic Circuit Design

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CHAPTER 17 17.1 a ( ) T = A β = ∞ | A v = 1 β = 5 | FGE = 0 b ( ) A = 10 80 20 = 10000 | T = 10000 0.2 ( ) = 2000 A v = A 1 + A β = 10000 1 + 2000 = 5.00 | FGE = 100% 1 + A β = 100% 2001 = 0.05% c ( ) T = 10 0.2 ( ) = 2 | A v = A 1 + A β = 10 1 + 2 = 3.33 | FGE = 100% 1 + 2 = 33.3% 17.2 a ( ) β = R 1 R 1 + R 2 = 1 k 101 k = 1 101 b ( ) T = A β = 10 86 20 1 101 = 198.6 | A v = A 1 + A β = 2 x 10 4 200 = 100 17.3 a ( ) β s ( ) = R 1 R 1 + R 2 = 1 k 101 k = 1 101 | T s ( ) = A β = 10 80 20 1 101 ⎟ = 99.0 A v = − R 2 R 1 A β 1 + A β = − 100 k 1 k 99 100 ⎟ = − 99 17.4 β s ( ) = Z 1 s ( ) Z 1 s ( ) + Z 2 s ( ) = R R + 1 sC = s s + 1 RC = s s + 5000 | A = 10 80 20 = 10 4 T s ( ) = A β = 10 4 s s + 5000 | A v = − Z 2 Z 1 A β 1 + A β = − 1 sRC 10 4 s s + 5000 1 + 10 4 s s + 5000 = − 1 RC 1 s + 0.5 Instead of a pole at the origin, the integrator has a low- pass response with a pole a ω = 0.5 rad/s. ©Richard C. Jaeger and Travis N. Blalock - 3/10/07 17-1

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