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Unformatted text preview: 7. (see attached) 8. (see above) 9. Absorbance = 2.2749 Concentration: 0.226 (obtained in experiment) = 2.2749x x = 0.099345 mg/mL 0.099345 mg/mL = mg (protein in pool of NDase)/ 2.72 mL (obtained in experiment) 0.2702184 mg protein in pool of NDase 10. a. 33.773% b. (0.2702184 mg/0.8 mg) 100%= 33.733% c. 34.936% (average percent yield for lab section). My yield (33.773%) was slightly lower. This may have been due to slight experimental errors (i.e. dust on the spectrophotometer cuvets, carelessness in iteratively determining the volume of pooled NDase). d. Knowing the percentage yield in protein purification allows a molecular biologist to gauge the validity of her work. Percentage yield provides raw feedback about a biologists experimental procedure. Absorbance vs. Concentration y = 2.2749x R 2 = 0.9992 0.5 1 1.5 2 2.5 0.5 1 1.5 NDase concentration (mg/mL) Absorbance at 550 nm...
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- Fall '08