Lecture 5 _08 Growth II

Lecture 5 _08 Growth II - Feb. 12 Reminders:...

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    Feb. 12 Reminders: Clickers/Blackboard First Midterm, Feb 21
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    Growth Generation Time The time required for a population to double (doubling time)  in number Ex.  Escherichia coli  double every 20 minutes Growth Rate Constant How many doublings per unit time (usually,  generations/hour) E. coli  in above example has a k of 3 gen/hr
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    Growth Dynamics Bacillus stearothermophilus Doubles every 10  minutes Time # Gen       # Bact 0       0 1 2 0 10        1 2 2 1 20        2 4 2 2 30        3 8 2 3 40        4 16 2 4 50        5 32 2 5 60        6 64 2 6
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    Growth Dynamics At 10 minutes per generation, how  many generations in a day? 144 How many bacteria?
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    Growth Dynamics 144 generations, so 2 144 2.2 X 10 43  bacteria = ~ 2.2 X 10 31  grams = ~ 2.4 X 10 25  Tons = ~  3000 times the mass of the earth!
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    Growth Dynamics To calculate numbers of bacteria  B = 2 n  :    n  = # of doublings  (generations)  B  = # of Bacteria  OR B = 2 kt k  = Growth Rate Constant           t  = time elapsed
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    Bacterial growth Generation time Amount of time for a doubling Usually in minutes per generation Growth rate constant, k Doublings per unit time Usually in doublings per hour
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  Growth Dynamics Bacillus stearothermophilus Doubles every 10 minutes GT = ? K = ?
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This note was uploaded on 05/19/2008 for the course BIOL 275 taught by Professor Sandoz/shreirer during the Spring '08 term at UMBC.

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Lecture 5 _08 Growth II - Feb. 12 Reminders:...

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