PHYS 262 Lab Report 2 - Lab Report 2 PHYS 262-003 Author NAME Partners NAME Date Phys 262-003 Lab Report 2 NAME Objective The purpose of this lab is to

PHYS 262 Lab Report 2 - Lab Report 2 PHYS 262-003 Author...

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Lab Report 2PHYS 262-003Author: NAMEPartners: NAMEDate: 9-24-14
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Phys 262-003Lab Report 2NAMEObjective: The purpose of this lab is to examine the electric field of two point charges and the electric field between two parallel conductors. The relationship between the electrical field and the equipotential surfaces will be mapped onto conducting paper. The electric field of the parallelconductors will be calculated using the rate of change of the voltage between the two conductors.This will also be mapped out on conducting paper.Theory: A charge placed in an electric field senses a vector force proportional to that electric field, E:F=qEEq. (1)If the charge, q, moves a short distance, Δs,in the electric field, then the work done can be described as:∆W=F∆ scosθ=qE∆ scosθEq. (2)Where θ is the angle of the movement from the field direction. The most work is done when the angle is zero, which signifies that the field and displacement are aligned. When the charge is moved at right angles of the field direction an angle of zero is achieved. The voltage between two close points in the field is defined as the negative of the work done per unit of change,∆V=−E ∆scosθEq. (3)If we move in the direction of the electrical field, θ=0, then equation 3 gives ΔV= -EΔs and E can be solved as:E=∆V∆sEq. (4)In this case, the magnitude of E, the electrical field, is equal to the rate of change in voltage and the direction of E is equal to the direction of the maximum rate of decrease in voltage. If we move across the electric field, making θ=90°, then voltage is constant in that direction and equation 3 gives ΔV=0. Lines of constant voltage are called equipotentials. They always appear perpendicular to the direction of the electric field. An example could be given by the electric field of a point charge. The field points away from a positive charge. These lines cross the equipotential lines at right angles and form concentric circles. The field points in the direction of decreasing voltage, so the highest potential is near the charge while the lower potential is further away.
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  • Summer '19
  • Physics, Charge, Electric charge, power supply, PHYS 262 Lab Report

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