PHYS 151Q.005 1-25-2008

# PHYS 151Q.005 1-25-2008 - 5sin(5 5 1 1(ln(5 5 2.3...

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Day 2 Fri 1-25-08 PHYS 151Q.005 IDEA I = interpret “eye” Read carefully/collect info D = Develop “Draw” Visualize Problem/Draw a diagram E = Evaluate “equation” Figure out which equations you need A = Assess “ask” Ask yourself if the answer makes sense Chapter 2 – Motion in a straight line 2.1 - Average Motion Displacement =Net distance from end point to starting point Has a direction Is a vector Unit is meter Average Velocity Unit is meter/second Is a vector Average Speed 2.2 - Velocity = Instantaneous velocity V= the limit as the change in t goes toward 0 V=

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2 5 5 5 2 Differentiation (5 ) 10 (cos(5 ))
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Unformatted text preview: 5sin(5 ) ( ) 5 1 1 (ln ) (5) 5 2.3 - Acceleration is a vector unit Change rate of velocity is Acceleration /sec Ex 2-2. A particle moving along the x t t t d t t dt d t t dt d e e dt d dt t t a m = = -= = = = 2 axis has a position given by x = (24t -2t2) m, where t is measured in sec. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero? (24 2 ) Find the deri x t t m =-vative of the given equation to find velocity 24 4 Find the derivative of the velocity equation to find acceleration 4 dx t v dt dx a dt =-= = - =...
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PHYS 151Q.005 1-25-2008 - 5sin(5 5 1 1(ln(5 5 2.3...

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