Ch12 answers

Ch12 answers - Ar = 0.083 kJ/K 12.43 max = 15.5% 12.47...

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Answers to Assigned Problems from Chapter Twelve 12.2 (a) mf N2 = 0.3218, mf CO2 = 0.6321, mf CH4 = 0.0461; (b) p N2 = 0.8 bar, p CO2 = 1.0 bar, p CH4 = 0.2 bar; (c) V = 3.618 m 3 12.5 (a) y CO2 = 0.5002, y CO = 0.3277, y O2 = 0.1721; (b) p CO2 = 10.004 psia, p CO = 6.554 psia, p O2 = 3.442 psia; (c) V = 146.2 ft 3 12.7 m O2 = 0.8256 kg; m N2 = 2.7142 kg; m He = 0.4716 kg 12.11 (a) mf N2 = 0.4, mf He = 0.6; (b) y N2 = 0.0870, y He = 0.9130; (c) Q = 337.3 Btu; (d) ds = 0.593 Btu/R 12.14 NO 12.26 (a) V Ar = 0.624 m 3 , V O2 = 0.166 m 3 ; (b) p f = 1.89 bar; (c) Q = -2.94 kJ; (d) dS
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Unformatted text preview: Ar = 0.083 kJ/K 12.43 max = 15.5% 12.47 Volumetric flow = 193,500 ft 3 /h 12.48 m condensed = 0.01014 lbm 12.65 (a) = 0.0081 kg-v/kg-da, = 43.6%; (b) = 0.0076 lbm-v/lbm-da, = 41.2%; (c) and (d) similar results to (a) and (b) respectively limited by the precision of the chart 12.66 (a) = 68%, = 0.0182 kg-v/kg-da, h = 76.3 kJ/kg-da; (b) = 0.0163 kg-v/kg-da, h = 71.5 kJ/kg-da, T wb = 24 C; (c) T dp = 15 C mwe 10/22/2007...
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