2007 Final

2007 Final - Chemistry 162 Final Exam May 7, 2007 Student...

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Unformatted text preview: Chemistry 162 Final Exam May 7, 2007 Student Name (Print): ___TAVSS_________________ Recitation Section Number: t Recitation Instructor: ____TAVSS______________ The exam booklet has 55 questions for credit and one additional question to check the color of your exam booklet. Please answer all 55 questions on the OpScan sheet. Use the best answer of the choices available. There is no penalty for guessing. At the end of the 3-hour exam period, please hand in only this top sheet and your OpScan form. If you finish early, please do not disturb your fellow students. A proctor will check your picture ID, OpScan form, signature and calculator during the exam. The use of calculators with permanent memories (graphing calculators), cell phones, pagers, PDAs or other electronic devices other than a basic scientific calculator is expressly forbidden. The last page of the booklet contains a periodic table along with other useful data. The use of any other notes or information on this test will be considered a violation of the Academic Honesty provisions of the student code. Exam scores will be posted as soon as possible. ON THE OpScan FORM (Use a #2 pencil or darker) Sec Per. Instr Sec Per. Instr 1. SIGN your name across the top of the form. 01 M3 RA 30 Th3 HS 2. Code the following information ( blacken circles) 03 M5 RA 31 Th3 ET Your Name (LAST NAME FIRST) 04 M5 LH 33 M6 RP Your RUTGERS ID NUMBER 06 W3 LH 34 M6 RA [Start under Box A and continue to Box I ] 07 W3 HS 36 W6 NM Your RECITATION SECTION NUMBER in K & L 08 W5 LH 37 M8 RP [Sections 01-08, code a 0 under box K ] 11 F3 NM 39 W8 NM Your EXAM FORM NUMBER under box P 17 M1 HS 19 M3 NM LH = L. Huebner, RP = R. Porcja, RA = R. Agarwal 20 M3 HS HS = H. Sangari, NM = N. Marky, ET = E. Tavss 23 W1 ET Periods: 1 = 9:30-10:25, 3 = 12:15-1:10 or 12:50-1:45 25 W3 ET 5 = 3:35-4:30, 6 = 5:15-6:10, 8 = 8:25p-9:20p 26 W3 NM Your EXAM FORM is 1 1 Chem 162-2007 Final exam + answers Chapter 22 Transition Metals and Coordination Chemistry Coordination Compounds How many of the following compounds exhibit geometric isomers? I. Pt(NH 3 ) 2 Cl 2 II. [Co(NH 3 ) 6 ]Cl 3 III. [Ni(NH 3 ) 4 (NO 2 ) 2 ] IV. K 2 [CoCl 4 ] A. B. 1 C . 2 D. 3 E. 4 I. Pt(NH 3 ) 2 Cl 2 In the square planar form, this molecule can exist as cis- and trans-isomers, which are geometric isomers. II. [Co(NH 3 ) 6 ]Cl 3 In the octahedral form, the six NH 3 groups occupy all possible positions. Hence, there are no cis-trans isomers. Therefore, there are no geometric isomers. III. [Ni(NH 3 ) 4 (NO 2 ) 2 ] In the octahedral form, the two nitro groups can be cis to each other or trans to each other. Hence, this molecule can exist as cis- and trans-isomers, which are geometric isomers....
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This note was uploaded on 05/22/2008 for the course CHEM 162 taught by Professor Siegal during the Spring '08 term at Rutgers.

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2007 Final - Chemistry 162 Final Exam May 7, 2007 Student...

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