2006 Exam 1

2006 Exam 1 - Chemistry 162 Exam I February 8 2006 Student...

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Chemistry 162 Exam I February 8, 2006 Student Name (Print): ___TAVSS_________________ Recitation Section Number: t Recitation Instructor: ___TAVSS_______________ The exam booklet has 25 questions for credit and one additional question to check the color of your exam booklet. Please answer all 26 questions on the OpScan sheet. Use the best answer of the choices available. There is no penalty for guessing. At the end of the 80-minute exam period, please hand in only this top sheet and your OpScan form. If you finish early, please do not disturb your fellow students. A proctor will check your picture ID, OpScan form, signature and calculator during the exam. The use of calculators with permanent memories (graphing calculators), cell phones, pagers, PDAs or other electronic devices other than a basic scientific calculator is expressly forbidden. The last page of the booklet contains a periodic table along with other useful data. The use of any other notes or information on this test will be considered a violation of the Academic Honesty provisions of the student code. Exam scores will be posted as soon as possible. ON THE OpScan FORM (Use a #2 pencil or darker) Sec Per. Instr Sec Per. Instr 1. SIGN your name across the top of the form. 01 M3 RA 30 Th3 HS 2. Code the following information ( blacken circles) 03 M5 RA 31 Th3 ET Your Name (LAST NAME FIRST) 04 M5 LH 33 M6 RP Your SOCIAL SECURITY NUMBER 06 W3 LH 34 M6 RA [Start under Box A and continue to Box I ] 07 W3 HS 36 W6 NM Your RECITATION SECTION NUMBER in 08 W5 LH 37 M8 RP [Sections 01-08, code a 0 under box K ] 11 F3 NM 39 W8 NM Your EXAM FORM NUMBER under box P 17 M1 HS 19 M3 NM LH = L. Huebner, RP = R. Porcja, RA = R. Agarwal 20 M3 HS HS = H. Sangari, TH = T. Hyde, NM = N. Marky 23 W1 ET ME = M. Esguerra, ET = E. Tavss 25 W3 ET Periods: 1 = 9:30-10:25, 3 = 12:15-1:10 or 12:50-1:45 26 W3 NM 5 = 3:35-4:30, 6 = 5:15-6:10, 8 = 8:25p-9:20p Your EXAM FORM is C162s06e1v1 1
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Your EXAM FORM is 1 Chem 162-2006 Hourly exam I + answers Chapter 12 – Chemical Kinetics Rates, rate constants, reaction orders, half-lives calculations Integrated rate law The half life of a first order reaction is 2.64s. How long must the reaction proceed before only 1.56% of the reactant remains? A. 2.64s B. 338s C. 10.6s D . 15.8s E. 26.4s First order reaction: t 1/2 = 0.693/k 2.64 = 0.693/k k = 0.2625 ln[C] t = -kt + ln[C] o ln[(0.0156)] t = (-0.2625 x t) + ln[1.00] o t = 15.85 s 2 Chem 162-2006 Hourly exam I + answers Chapter 11 – Properties of solutions Colligative Properties Concepts Boiling Point Colligative properties (freezing point depression, boiling point elevation, etc.) depend on A. The properties of the solvent and the solute. B.
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2006 Exam 1 - Chemistry 162 Exam I February 8 2006 Student...

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